public static void main(String[] args) {
List<GroupDetailDTO> list = new ArrayList<>();
GroupDetailDTO dto1 = new GroupDetailDTO();
dto1.setHeadsetId(1);
dto1.setTime("2020-01-03");
dto1.setActConcreteTime("a");
dto1.setPlayed(1);
list.add(dto1);
GroupDetailDTO dto2 = new GroupDetailDTO();
dto2.setHeadsetId(1);
dto2.setTime("2020-01-01");
dto2.setActConcreteTime("b");
dto2.setPlayed(1);
list.add(dto2);
GroupDetailDTO dto3 = new GroupDetailDTO();
dto3.setHeadsetId(1);
dto3.setTime("2020-01-02");
dto3.setActConcreteTime("c");
dto3.setPlayed(1);
list.add(dto3);
GroupDetailDTO dto4 = new GroupDetailDTO();
dto4.setHeadsetId(2);
dto4.setTime("2020-01-01");
dto4.setActConcreteTime("d");
dto4.setPlayed(4);
list.add(dto4);
Map<GroupDetailDTO, Integer> collect = list.stream().collect(Collectors.groupingBy(o -> new GroupDetailDTO(o.getHeadsetId(), o.getTime()), TreeMap::new, Collectors.summingInt(o -> o.getPlayed())));
collect.forEach((k, v) -> {
System.out.println(k + "@@@" + v);
});
}
@Data
public class GroupDetailDTO implements Comparable<GroupDetailDTO> {
private Integer headsetId;
private String actConcreteTime;
private String time;
private Integer played;
public GroupDetailDTO() {
}
public GroupDetailDTO(Integer headsetId, String time) {
this.headsetId = headsetId;
this.time = time;
}
@Override
public int compareTo(GroupDetailDTO o) {
String a = this.headsetId + "|" + this.getTime();
String b = o.getHeadsetId() + "|" + o.getTime();
return a.compareTo(b);
// return this.getTime().compareTo(o.gtTime());
}
}
結(jié)果:
上述代碼實(shí)現(xiàn)對對象GroupDetailDTO按設(shè)備和時間分組求played的和,并且按時間排序了惭墓。當(dāng)初想著既然是按時間排序那么compareTo方法直接使用
return this.getTime().compareTo(o.getTime());
但是結(jié)果不正確
分析:分組求和時如果使用了排序坛梁,那么分組時對相同屬性的合并將直接根據(jù)compareTo返回的結(jié)果合并對象,所以如果用上述方法將產(chǎn)生相同的時間直接合并腊凶,而不是new GroupDetailDTO(o.getHeadsetId(), o.getTime())里面的兩個屬性都相同才合并划咐。