Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
考這題純粹就是為了陰人壕探，我確實也沒想到結(jié)尾會是空格的case: "a "。
public int lengthOfLastWord(String s) {
if (s == null || s.length() == 0) return 0;
//這邊陰人瘾杭，結(jié)尾有可能是是空格"a "
int len = 0, tail = s.length() - 1;
while (tail >= 0 && s.charAt(tail) == ' ')
tail--;
while (tail >= 0 && s.charAt(tail) != ' ') {
len++;
tail--;
}
return len;
}
或者：
public int lengthOfLastWord(String s) {
return s.trim().length()-s.trim().lastIndexOf(" ")-1;
}
