建表
create table student(s_id string,s_name string,s_birth string,s_sex string) row format delimited fields terminated by '\t';

create table course(c_id string,c_name string,t_id string) row format delimited fields terminated by '\t';

create table teacher(t_id string,t_name string) row format delimited fields terminated by '\t';

create table score(s_id string,c_id string,s_score int) row format delimited fields terminated by '\t';
生成數(shù)據(jù)

vi /export/data/hivedatas/student.csv

01 趙雷 1990-01-01 男
02 錢電 1990-12-21 男
03 孫風(fēng) 1990-05-20 男
04 李云 1990-08-06 男
05 周梅 1991-12-01 女
06 吳蘭 1992-03-01 女
07 鄭竹 1989-07-01 女
08 王菊 1990-01-20 女
vi /export/data/hivedatas/course.csv
01 語文 02
02 數(shù)學(xué) 01
03 英語 03
vi /export/data/hivedatas/teacher.csv
01 張三
02 李四
03 王五
vi /export/data/hivedatas/score.csv
01 01 80
01 02 90
01 03 99
02 01 70
02 02 60
02 03 80
03 01 80
03 02 80
03 03 80
04 01 50
04 02 30
04 03 20
05 01 76
05 02 87
06 01 31
06 03 34
07 02 89
07 03 98
導(dǎo)數(shù)據(jù)到hive
load data local inpath '/export/data/hivedatas/student.csv' into table student;

load data local inpath '/export/data/hivedatas/course.csv' into table course;

load data local inpath '/export/data/hivedatas/teacher.csv' into table teacher;

load data local inpath '/export/data/hivedatas/score.csv' into table score;
–注:–hive查詢語法
SELECT [ALL | DISTINCT] select_expr, select_expr, ...
FROM table_reference
[WHERE where_condition]
[GROUP BY col_list [HAVING condition]]
[CLUSTER BY col_list
| [DISTRIBUTE BY col_list] [SORT BY| ORDER BY col_list]
]
[LIMIT number]
– 1助隧、查詢"01"課程比"02"課程成績高的學(xué)生的信息及課程分?jǐn)?shù):
select student.,a.s_score as 01_score,b.s_score as 02_score
from student
join score a on student.s_id=a.s_id and a.c_id='01'
left join score b on student.s_id=b.s_id and b.c_id='02'
where a.s_score>b.s_score;
–答案2
select student.,a.s_score as 01_score,b.s_score as 02_score
from student
join score a on a.c_id='01'
join score b on b.c_id='02'
where a.s_id=student.s_id and b.s_id=student.s_id and a.s_score>b.s_score;
– 2哲鸳、查詢"01"課程比"02"課程成績低的學(xué)生的信息及課程分?jǐn)?shù):
select student.,a.s_score as 01_score,b.s_score as 02_score
from student
join score a on student.s_id=a.s_id and a.c_id='01'
left join score b on student.s_id=b.s_id and b.c_id='02'
where a.s_score<b.s_score;
–答案2
select student.,a.s_score as 01_score,b.s_score as 02_score
from student
join score a on a.c_id='01'
join score b on b.c_id='02'
where a.s_id=student.s_id and b.s_id=student.s_id and a.s_score<b.s_score;
– 3胯努、查詢平均成績大于等于60分的同學(xué)的學(xué)生編號和學(xué)生姓名和平均成績:

select student.s_id,student.s_name,tmp.平均成績 from student
join (
select score.s_id,round(avg(score.s_score),1)as 平均成績
from score group by s_id)as tmp
on tmp.平均成績>=60
where student.s_id = tmp.s_id
–答案2

select student.s_id,student.s_name,round(avg (score.s_score),1) as 平均成績 from student
join score on student.s_id = score.s_id
group by student.s_id,student.s_name
having avg (score.s_score) >= 60;
– 4翅敌、查詢平均成績小于60分的同學(xué)的學(xué)生編號和學(xué)生姓名和平均成績:
– (包括有成績的和無成績的)

select student.s_id,student.s_name,tmp.avgScore from student
join (
select score.s_id,round(avg(score.s_score),1)as avgScore from score group by s_id)as tmp
on tmp.avgScore < 60
where student.s_id=tmp.s_id
union all
select s2.s_id,s2.s_name,0 as avgScore from student s2
where s2.s_id not in
(select distinct sc2.s_id from score sc2);
–答案2

select score.s_id,student.s_name,round(avg (score.s_score),1) as avgScore from student
inner join score on student.s_id=score.s_id
group by score.s_id,student.s_name
having avg (score.s_score) < 60
union all
select s2.s_id,s2.s_name,0 as avgScore from student s2
where s2.s_id not in
(select distinct sc2.s_id from score sc2);
– 5寞宫、查詢所有同學(xué)的學(xué)生編號伐憾、學(xué)生姓名眯漩、選課總數(shù)、所有課程的總成績:

select student.s_id,student.s_name,(count(score.c_id) )as total_count,sum(score.s_score)as total_score
from student
left join score on student.s_id=score.s_id
group by student.s_id,student.s_name ;
– 6芯肤、查詢"李"姓老師的數(shù)量:

select t_name,count(1) from teacher where t_name like '李%' group by t_name;
– 7、查詢學(xué)過"張三"老師授課的同學(xué)的信息:

select student.* from student
join score on student.s_id =score.s_id
join course on course.c_id=score.c_id
join teacher on course.t_id=teacher.t_id and t_name='張三';
– 8压鉴、查詢沒學(xué)過"張三"老師授課的同學(xué)的信息:

select student.* from student
left join (select s_id from score
join course on course.c_id=score.c_id
join teacher on course.t_id=teacher.t_id and t_name='張三')tmp
on student.s_id =tmp.s_id
where tmp.s_id is null;
– 9崖咨、查詢學(xué)過編號為"01"并且也學(xué)過編號為"02"的課程的同學(xué)的信息:

select * from student
join (select s_id from score where c_id =1 )tmp1
on student.s_id=tmp1.s_id
join (select s_id from score where c_id =2 )tmp2
on student.s_id=tmp2.s_id;
– 10、查詢學(xué)過編號為"01"但是沒有學(xué)過編號為"02"的課程的同學(xué)的信息:

select student.* from student
join (select s_id from score where c_id =1 )tmp1
on student.s_id=tmp1.s_id
left join (select s_id from score where c_id =2 )tmp2
on student.s_id =tmp2.s_id
where tmp2.s_id is null;
– 11油吭、查詢沒有學(xué)全所有課程的同學(xué)的信息:
–先查詢出課程的總數(shù)量

select count(1) from course;
–再查詢所需結(jié)果

select student.* from student
left join(
select s_id
from score
group by s_id
having count(c_id)=3)tmp
on student.s_id=tmp.s_id
where tmp.s_id is null;
–方法二(一步到位):

select student.* from student
join (select count(c_id)num1 from course)tmp1
left join(
select s_id,count(c_id)num2
from score group by s_id)tmp2
on student.s_id=tmp2.s_id and tmp1.num1=tmp2.num2
where tmp2.s_id is null;
– 12击蹲、查詢至少有一門課與學(xué)號為"01"的同學(xué)所學(xué)相同的同學(xué)的信息:

select student.* from student
join (select c_id from score where score.s_id=01)tmp1
join (select s_id,c_id from score)tmp2
on tmp1.c_id =tmp2.c_id and student.s_id =tmp2.s_id
where student.s_id not in('01')
group by student.s_id,s_name,s_birth,s_sex;
– 13、查詢和"01"號的同學(xué)學(xué)習(xí)的課程完全相同的其他同學(xué)的信息:
–備注:hive不支持group_concat方法,可用 concat_ws(’|’, collect_set(str)) 實(shí)現(xiàn)

select student.*,tmp1.course_id from student
join (select s_id ,concat_ws('|', collect_set(c_id)) course_id from score
group by s_id having s_id not in (1))tmp1
on student.s_id = tmp1.s_id
join (select concat_ws('|', collect_set(c_id)) course_id2
from score where s_id=1)tmp2
on tmp1.course_id = tmp2.course_id2;
– 14婉宰、查詢沒學(xué)過"張三"老師講授的任一門課程的學(xué)生姓名:

select student.* from student
left join (select s_id from score
join (select c_id from course join teacher on course.t_id=teacher.t_id and t_name='張三')tmp2
on score.c_id=tmp2.c_id )tmp
on student.s_id = tmp.s_id
where tmp.s_id is null;
– 15歌豺、查詢兩門及其以上不及格課程的同學(xué)的學(xué)號，姓名及其平均成績:

select student.s_id,student.s_name,tmp.avg_score from student
inner join (select s_id from score
where s_score<60
group by score.s_id having count(s_id)>1)tmp2
on student.s_id = tmp2.s_id
left join (
select s_id,round(AVG (score.s_score)) avg_score
from score group by s_id)tmp
on tmp.s_id=student.s_id;
– 16心包、檢索"01"課程分?jǐn)?shù)小于60类咧，按分?jǐn)?shù)降序排列的學(xué)生信息:

select student.*,s_score from student,score
where student.s_id=score.s_id and s_score<60 and c_id='01'
order by s_score desc;
– 17、按平均成績從高到低顯示所有學(xué)生的所有課程的成績以及平均成績:

select a.s_id,tmp1.s_score as chinese,tmp2.s_score as math,tmp3.s_score as english,
round(avg (a.s_score),2) as avgScore
from score a
left join (select s_id,s_score from score s1 where c_id='01')tmp1 on tmp1.s_id=a.s_id
left join (select s_id,s_score from score s2 where c_id='02')tmp2 on tmp2.s_id=a.s_id
left join (select s_id,s_score from score s3 where c_id='03')tmp3 on tmp3.s_id=a.s_id
group by a.s_id,tmp1.s_score,tmp2.s_score,tmp3.s_score order by avgScore desc;
– 18.查詢各科成績最高分谴咸、最低分和平均分：以如下形式顯示：課程ID轮听，課程name，最高分岭佳，最低分血巍，平均分，及格率珊随，中等率述寡，優(yōu)良率，優(yōu)秀率:
–及格為>=60叶洞，中等為：70-80鲫凶，優(yōu)良為：80-90，優(yōu)秀為：>=90
select course.c_id,course.c_name,tmp.maxScore,tmp.minScore,tmp.avgScore,tmp.passRate,tmp.moderate,tmp.goodRate,tmp.excellentRates from course
join(select c_id,max(s_score) as maxScore,min(s_score)as minScore,
round(avg(s_score),2) avgScore,
round(sum(case when s_score>=60 then 1 else 0 end)/count(c_id),2)passRate,
round(sum(case when s_score>=60 and s_score<70 then 1 else 0 end)/count(c_id),2) moderate,
round(sum(case when s_score>=70 and s_score<80 then 1 else 0 end)/count(c_id),2) goodRate,
round(sum(case when s_score>=80 and s_score<90 then 1 else 0 end)/count(c_id),2) excellentRates
from score group by c_id)tmp on tmp.c_id=course.c_id;
– 19衩辟、按各科成績進(jìn)行排序螟炫，并顯示排名:
– row_number() over()分組排序功能(mysql沒有該方法)

select s1.,row_number()over(order by s1.s_score desc) Ranking
from score s1 where s1.c_id='01'order by noRanking asc
union all select s2.,row_number()over(order by s2.s_score desc) Ranking
from score s2 where s2.c_id='02'order by noRanking asc
union all select s3.*,row_number()over(order by s3.s_score desc) Ranking
from score s3 where s3.c_id='03'order by noRanking asc;
– 20、查詢學(xué)生的總成績并進(jìn)行排名:

select score.s_id,s_name,sum(s_score) sumscore,row_number()over(order by sum(s_score) desc) Ranking
from score ,student
where score.s_id=student.s_id
group by score.s_id,s_name order by sumscore desc;
– 21艺晴、查詢不同老師所教不同課程平均分從高到低顯示:
– 方法1

select course.c_id,course.t_id,t_name,round(avg(s_score),2)as avgscore from course
join teacher on teacher.t_id=course.t_id
join score on course.c_id=score.c_id
group by course.c_id,course.t_id,t_name order by avgscore desc;
– 方法2

select course.c_id,course.t_id,t_name,round(avg(s_score),2)as avgscore from course,teacher,score
where teacher.t_id=course.t_id and course.c_id=score.c_id
group by course.c_id,course.t_id,t_name order by avgscore desc;
– 22昼钻、查詢所有課程的成績第2名到第3名的學(xué)生信息及該課程成績:

select tmp1.* from
(select * from score where c_id='01' order by s_score desc limit 3)tmp1
order by s_score asc limit 2
union all select tmp2.* from
(select * from score where c_id='02' order by s_score desc limit 3)tmp2
order by s_score asc limit 2
union all select tmp3.* from
(select * from score where c_id='03' order by s_score desc limit 3)tmp3
order by s_score asc limit 2;
– 23、統(tǒng)計(jì)各科成績各分?jǐn)?shù)段人數(shù)：課程編號,課程名稱,[100-85],[85-70],[70-60],[0-60]及所占百分比

select c.c_id,c.c_name,tmp1.s0_60, tmp1.percentum,tmp2.s60_70, tmp2.percentum,tmp3.s70_85, tmp3.percentum,tmp4.s85_100, tmp4.percentum
from course c
join(select c_id,sum(case when s_score<60 then 1 else 0 end )as s0_60,
round(100sum(case when s_score<60 then 1 else 0 end )/count(c_id),2)as percentum
from score group by c_id)tmp1 on tmp1.c_id =c.c_id
left join(select c_id,sum(case when s_score<70 and s_score>=60 then 1 else 0 end )as s60_70,
round(100sum(case when s_score<70 and s_score>=60 then 1 else 0 end )/count(c_id),2)as percentum
from score group by c_id)tmp2 on tmp2.c_id =c.c_id
left join(select c_id,sum(case when s_score<85 and s_score>=70 then 1 else 0 end )as s70_85,
round(100sum(case when s_score<85 and s_score>=70 then 1 else 0 end )/count(c_id),2)as percentum
from score group by c_id)tmp3 on tmp3.c_id =c.c_id
left join(select c_id,sum(case when s_score>=85 then 1 else 0 end )as s85_100,
round(100sum(case when s_score>=85 then 1 else 0 end )/count(c_id),2)as percentum
from score group by c_id)tmp4 on tmp4.c_id =c.c_id;
– 24封寞、查詢學(xué)生平均成績及其名次:

select tmp.*,row_number()over(order by tmp.avgScore desc) Ranking from
(select student.s_id,
student.s_name,
round(avg(score.s_score),2) as avgScore
from student join score
on student.s_id=score.s_id
group by student.s_id,student.s_name)tmp
order by avgScore desc;
– 25然评、查詢各科成績前三名的記錄

–課程id為01的前三名

select score.c_id,course.c_name,student.s_name,s_score from score
join student on student.s_id=score.s_id
join course on score.c_id='01' and course.c_id=score.c_id
order by s_score desc limit 3;
–課程id為02的前三名

select score.c_id,course.c_name,student.s_name,s_score
from score
join student on student.s_id=score.s_id
join course on score.c_id='02' and course.c_id=score.c_id
order by s_score desc limit 3;
–課程id為03的前三名

select score.c_id,course.c_name,student.s_name,s_score
from score
join student on student.s_id=score.s_id
join course on score.c_id='03' and course.c_id=score.c_id
order by s_score desc limit 3;
– 26、查詢每門課程被選修的學(xué)生數(shù):

select c.c_id,c.c_name,tmp.number from course c
join (select c_id,count(1) as number from score
where score.s_score<60 group by score.c_id)tmp
on tmp.c_id=c.c_id;
– 27狈究、查詢出只有兩門課程的全部學(xué)生的學(xué)號和姓名:

select st.s_id,st.s_name from student st
join (select s_id from score group by s_id having count(c_id) =2)tmp
on st.s_id=tmp.s_id;
– 28碗淌、查詢男生、女生人數(shù):

select tmp1.man,tmp2.women from
(select count(1) as man from student where s_sex='男')tmp1,
(select count(1) as women from student where s_sex='女')tmp2;
– 29、查詢名字中含有"風(fēng)"字的學(xué)生信息:

select * from student where s_name like '%風(fēng)%';
– 30亿眠、查詢同名同性學(xué)生名單碎罚，并統(tǒng)計(jì)同名人數(shù):

select s1.s_id,s1.s_name,s1.s_sex,count(*) as sameName
from student s1,student s2
where s1.s_name=s2.s_name and s1.s_id<>s2.s_id and s1.s_sex=s2.s_sex
group by s1.s_id,s1.s_name,s1.s_sex;
– 31、查詢1990年出生的學(xué)生名單:

select * from student where s_birth like '1990%';
– 32缕探、查詢每門課程的平均成績魂莫，結(jié)果按平均成績降序排列，平均成績相同時爹耗，按課程編號升序排列:

select score.c_id,c_name,round(avg(s_score),2) as avgScore from score
join course on score.c_id=course.c_id
group by score.c_id,c_name order by avgScore desc,score.c_id asc;
– 33、查詢平均成績大于等于85的所有學(xué)生的學(xué)號谜喊、姓名和平均成績:

select score.s_id,s_name,round(avg(s_score),2)as avgScore from score
join student on student.s_id=score.s_id
group by score.s_id,s_name having avg(s_score) >= 85;
– 34潭兽、查詢課程名稱為"數(shù)學(xué)"，且分?jǐn)?shù)低于60的學(xué)生姓名和分?jǐn)?shù):

select s_name,s_score as mathScore from student
join (select s_id,s_score
from score,course
where score.c_id=course.c_id and c_name='數(shù)學(xué)')tmp
on tmp.s_score < 60 and student.s_id=tmp.s_id;
– 35斗遏、查詢所有學(xué)生的課程及分?jǐn)?shù)情況:

select a.s_name,
SUM(case c.c_name when '語文' then b.s_score else 0 end ) as chainese,
SUM(case c.c_name when '數(shù)學(xué)' then b.s_score else 0 end ) as math,
SUM(case c.c_name when '英語' then b.s_score else 0 end ) as english,
SUM(b.s_score) as sumScore
from student a
join score b on a.s_id=b.s_id
join course c on b.c_id=c.c_id
group by s_name,a.s_id;
– 36山卦、查詢?nèi)魏我婚T課程成績在70分以上的學(xué)生姓名、課程名稱和分?jǐn)?shù):

select student.s_id,s_name,c_name,s_score from student
join (select sc.* from score sc
left join(select s_id from score where s_score < 70 group by s_id)tmp
on sc.s_id=tmp.s_id where tmp.s_id is null)tmp2
on student.s_id=tmp2.s_id
join course on tmp2.c_id=course.c_id
order by s_id;

-- 查詢?nèi)考案竦男畔?/strong>
select sc.* from score sc
left join(select s_id from score where s_score < 60 group by s_id)tmp
on sc.s_id=tmp.s_id
where tmp.s_id is null;
-- 或(效率低)
select sc.* from score sc
where sc.s_id not in (select s_id from score where s_score < 60 group by s_id);