1.一張紙的厚度大約是0.08mm偶器，對(duì)折多少次之后能達(dá)到珠穆朗瑪峰的高度（8848.13米）搀矫？

thick = 0.08/1000
n=0
while thick<8848.13:
    n += 1
    thick = thick*2

print("對(duì)折",n,"次")

2. 古典問(wèn)題：有一對(duì)兔子官觅，從出生后第3個(gè)月起每個(gè)月都生一對(duì)兔子刑峡， 小兔子長(zhǎng)到第三個(gè)月后每個(gè)月又生一對(duì)兔子洋闽，假如兔子都不死，問(wèn)每個(gè)月的兔子總數(shù)為多少突梦？

a1 = 0
a2 = 1
month = int(input("輸入第幾個(gè)月"))
for i in range(1,month):
    t = a1 + a2
    a1 = a2
    a2 = t
    print("第",i,"個(gè)月",a1)

3. 將一個(gè)正整數(shù)分解質(zhì)因數(shù)诫舅。例如:輸入90,打印出90=2x3x3x5。

num = int(input("請(qǐng)輸入正整數(shù)"))
k = 2
for i in range(2,num):
    while k != num:
        if num % k == 0:
            print(k,end='*')
            num = int(num/k)
            # print(num)
        else :
            k += 1
print(num)

4. 輸入兩個(gè)正整數(shù)m和n宫患，求其最大公約數(shù)和最小公倍數(shù)刊懈。 程序分析：利用輾除法。

m = 45
n = 20
m1 = m
n1 = n 

if m%n == 0 :
    print("最大公約數(shù)",n)
    print("最小公倍數(shù)",m)
else:
    while m % n!=0:
        t = m%n
        m,n= n,t
    print("最大公約數(shù)為",t)
    print("最小公倍數(shù)",int(m1*n1/t))

5.一個(gè)數(shù)如果恰好等于它的因子之和娃闲，這個(gè)數(shù)就稱為 "完數(shù) "虚汛。例如6=1＋2＋3. 編程 找出1000以內(nèi)的所有完數(shù)

for num in range(5,1000):
    n = 1
    sum = 0
    while n<num:
        if num % n == 0:
            sum = sum+n
        n += 1
    if sum == num:
        print(num)

6.輸入某年某月某日，判斷這一天是這一年的第幾天皇帮？ 程序分析：以3月5日為例卷哩，應(yīng)該先把前兩個(gè)月的加起來(lái)，然后再加上5天即本年的第幾天属拾，特殊情況将谊，閏年且輸入月份大于3時(shí)需考慮多加一天冷溶。

year = int(input('輸入年份'))
month = int(input('輸入月份'))
day = int(input('輸入日期'))
if (year%4==0 and year%100 ==0) or year%400==0:
    if month == 1:
        print('這是今年第：',day,'天')
    elif month == 2:
        print('這是今年第：',day+31,'天')
    elif month == 3:
        print('這是今年第：',day+31+29,'天')
    elif month == 4:
        print('這是今年第：',day+31+29+31,'天')
    elif month == 5:
        print('這是今年第：',day+31+29+31+30,'天')
    elif month == 6:
        print('這是今年第：',day+31+29+31+30+31,'天')
    elif month == 7:
        print('這是今年第：',day+31+29+31+30+31+30,'天')
    elif month == 8:
        print('這是今年第：',day+31+29+31+30+31+30+31,'天')
    elif month == 9:
        print('這是今年第：',day+31+29+31+30+31+30+31+31,'天')
    elif month == 10:
        print('這是今年第：',day+31+29+31+30+31+30+31+31+30,'天')
    elif month == 11:
        print('這是今年第：',day+31+29+31+30+31+30+31+31+30+31,'天')
    elif month == 12:
        print('這是今年第：',day+31+29+31+30+31+30+31+31+30+31+30,'天')
else:
    if month == 1:
        print('這是今年第：',day,'天')
    elif month == 2:
        print('這是今年第：',day+31,'天')
    elif month == 3:
        print('這是今年第：',day+31+29-1,'天')
    elif month == 4:
        print('這是今年第：',day+31+29+31-1,'天')
    elif month == 5:
        print('這是今年第：',day+31+29+31+30-1,'天')
    elif month == 6:
        print('這是今年第：',day+31+29+31+30+31-1,'天')
    elif month == 7:
        print('這是今年第：',day+31+29+31+30+31+30-1,'天')
    elif month == 8:
        print('這是今年第：',day+31+29+31+30+31+30+31-1,'天')
    elif month == 9:
        print('這是今年第：',day+31+29+31+30+31+30+31+31-1,'天')
    elif month == 10:
        print('這是今年第：',day+31+29+31+30+31+30+31+31+30-1,'天')
    elif month == 11:
        print('這是今年第：',day+31+29+31+30+31+30+31+31+30+31-1,'天')
    elif month == 12:
        print('這是今年第：',day+31+29+31+30+31+30+31+31+30+31+30-1,'天')

7.某個(gè)公司采用公用電話傳遞數(shù)據(jù)，數(shù)據(jù)是四位的整數(shù)尊浓，在傳遞過(guò)程中是加密的逞频，加密規(guī)則如下： 每位數(shù)字都加上5,然后用和除以10的余數(shù)代替該數(shù)字，再將第一位和第四位交換栋齿，第二位和第三位交換虏劲。求輸入的四位整數(shù)加密后的值

num = 4567
a = num%10
print(a)
b = int(num/10)%10
print(b)
c = int(num/100)%10
print(c)
d = int(num/1000)%10
print(d)
a = (a+5)%10
b = (b+5)%10
c = (c+5)%10
d = (d+5)%10
print(a*1000 +b*100+c *10+d)