Determine if a 9x9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:

1、Each row must contain the digits 1-9 without repetition.
2煤痕、Each column must contain the digits 1-9 without repetition.
3昙楚、Each of the 9 3x3 sub-boxes of the grid must contain the digits 1-9 without repetition.

A partially filled sudoku which is valid.

The Sudoku board could be partially filled, where empty cells are filled with the character '.'.

Example 1:

Input:
[
["5","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
Output: true

Example 2:

Input:
[
["8","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
Output: false
Explanation: Same as Example 1, except with the 5 in the top left corner being
modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.
Note:

A Sudoku board (partially filled) could be valid but is not necessarily solvable.
Only the filled cells need to be validated according to the mentioned rules.
The given board contain only digits 1-9 and the character '.'.
The given board size is always 9x9.

AC代碼

bool row(vector<vector<char>>& board) {
    int a[10];
    for (int i = 0; i < board.size(); ++i) {
        memset(a, 0, sizeof(a));
        for (int j = 0; j < board[i].size(); j++) {
            if (board[i][j] == '.')
                a[0]++;
            else {
                a[board[i][j] - '0']++;
                if (a[board[i][j] - '0'] > 1) return false;
            }
        }
    }
    return true;
}

bool col(vector<vector<char>>& board) {
    int a[10];
    for (int i = 0; i < board.size(); ++i) {  //每一列
        memset(a, 0, sizeof(a));
        for (int j = 0; j < board[i].size(); j++) {  //每一行
            if (board[j][i] == '.')
                a[0]++;
            else {
                a[board[j][i] - '0']++;
                if (a[board[j][i] - '0'] > 1) return false;
            }
        }
    }
    return true;
}

bool sub(vector<vector<char>>& board) {
    int a[10];
    for (int i = 0; i < 9; i += 3) {
        for (int j = 0; j < 9; j += 3) {
            memset(a, 0, sizeof(a));
            for (int ib = 0; ib < 3; ++ib) {
                for (int jb = 0; jb < 3; jb++) {
                    if (board[i + ib][j + jb] == '.')
                        a[0]++;
                    else {
                        a[board[i + ib][j + jb] - '0']++;
                        if (a[board[i + ib][j + jb] - '0'] > 1) return false;
                    }
                }
            }
        }
    }
    return true;
}

class Solution {
public:
    bool isValidSudoku(vector<vector<char>>& board) {
        return (row(board) && col(board) && sub(board));
    }
};

總結(jié)

老老實實實現(xiàn)三個條件即可