https://leetcode.com/problems/maximum-subarray/
Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
Example:
Input: [-2,1,-3,4,-1,2,1,-5,4],
Output: 6
Explanation: [4,-1,2,1] has the largest sum = 6.
Follow up:
If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
d[i] = 以 i 結(jié)尾的最大子序列的值
d[i] = max(0, d[i-1]) + nums[i]
初始條件：d[0] = nums[0]
class Solution {
public:
int maxSubArray(vector<int>& nums) {
int d[100005];
int n = nums.size();
d[0] = nums[0];
for (int i = 1; i < n; i++) {
d[i] = max(0, d[i-1]) + nums[i];
}
int ans = d[0];
for (int i = 1; i < n; i++) {
ans = (ans > d[i]) ? ans : d[i];
}
return ans;
}
};
