Screenshot from 2016-02-22 23:26:29.png
My code:
public class Solution {
public void wiggleSort(int[] nums) {
if (nums == null || nums.length == 0)
return;
Arrays.sort(nums);
for (int i = 2; i < nums.length; i += 2) {
int temp = nums[i];
nums[i] = nums[i - 1];
nums[i - 1] = temp;
}
}
}
沒做出來。允睹。帮毁。
今天狀態(tài)真的很差汛蝙。不做了。
Anyway, Good luck, Richardo!
My code:
public class Solution {
public void wiggleSort(int[] nums) {
if (nums == null || nums.length <= 1) {
return;
}
for (int i = 0; i < nums.length - 1; i += 2) {
if (nums[i] > nums[i + 1]){
swap(nums, i, i + 1);
}
}
for (int i = 1; i < nums.length - 1; i += 2) {
if (nums[i] < nums[i + 1]) {
swap(nums, i, i + 1);
}
}
}
private void swap(int[] nums, int left, int right) {
int temp = nums[right];
nums[right] = nums[left];
nums[left] = temp;
}
}
之前的做法比較慢娃循，O(n log n)
然后看了答案炕檩，
參考：
https://discuss.leetcode.com/topic/40813/1ms-java-solution-with-clear-example
發(fā)現(xiàn)有O(n)的做法。也是神奇捌斧。
Anyway, Good luck, Richardo! -- 09/04/2016
