如何獲取前n周的開始與結(jié)束時間巧婶？

def get_time_range(pre_n_week):
    """
    獲取前n周時間范圍（開始0點乾颁，結(jié)束24點）
    :param pre_n_week:
    :return: 毫秒
    """
    today = datetime.date.today()
    # n周開始日期
    s = today - datetime.timedelta(days=today.weekday() + 7 * pre_n_week)
    # n周結(jié)束日期
    e = s + datetime.timedelta(days=6)

    # 0點
    start_time = datetime.datetime.combine(date=s, time=datetime.time.min)
    end_time = datetime.datetime.combine(date=e, time=datetime.time.max)

    gte = int(round(start_time.timestamp()*1000))
    lte = int(round(end_time.timestamp()*1000))+86400000-1
    return gte, lte
 

效果如下，可以根據(jù)不同的格式（時間戳艺栈，毫秒等）需求自行處理英岭。

屏幕快照 2019-12-20 14.27.48.png

假定每周都是從周六開始，周五結(jié)束怎么獲取每周的日期范圍湿右？

def get_week_range(pre_n_week=0, simple_date=True):
    """
    獲取前n周時間范圍(每周始于周六巴席，至周五終止）
    :param pre_n_week:
    :param simple_date:簡單日期格式如2020-3-21
    :return:本周開始，本周結(jié)束诅需，當(dāng)前是本周第幾天
    """
    offset = 2 #提前2天（理論上可以修改你期望的值漾唉，其它的沒有測試）
    today = datetime.date.today()
    # n周開始日期
    s = today - datetime.timedelta(days=(today.weekday() + offset) % 7 + 7 * pre_n_week)
    # n周結(jié)束日期
    e = s + datetime.timedelta(days=6)

    n = (today-s).days
    if simple_date:
        return s.strftime("%Y-%m-%d"), e.strftime("%Y-%m-%d"), n
    return s, e, n

# 測試代碼
@pytest.mark.parametrize('pre_n_week, assume_date, expected_s, expected_e',
                         [
                             (0, '2020-05-01', '2020-04-25', '2020-05-01'),
                             (1, '2020-05-01', '2020-04-18', '2020-04-24'),
                             (0, '2020-04-30', '2020-04-25', '2020-05-01'),
                             (1, '2020-04-30', '2020-04-18', '2020-04-24'),
                             (0, '2020-05-15', '2020-05-09', '2020-05-15'),
                             (0, '2020-05-02', '2020-05-02', '2020-05-08'),
                             (1, '2020-05-02', '2020-04-25', '2020-05-01'),
                             (0, '2020-05-03', '2020-05-02', '2020-05-08'),
                             (1, '2020-05-03', '2020-04-25', '2020-05-01'),
                             (0, '2020-05-04', '2020-05-02', '2020-05-08'),
                         ])
def test_get_week_range(pre_n_week, assume_date, expected_s, expected_e):
    t = datetime.strptime(assume_date, '%Y-%m-%d')
    ts = (t - datetime(year=1970, month=1, day=1)).total_seconds()
    with freeze_time(ts):
        s, e, n = get_week_range(pre_n_week=pre_n_week)
        assert s == expected_s
        assert e == expected_e