看到一篇文章推薦讲逛，我找了本 Automate the Boring Stuff with Python
每天學(xué)一點，今后碰到什么重復(fù)性的工作時希望能用得上……
第3章（函數(shù)）練習(xí)項目：考拉茲數(shù)列
The Collatz Sequence
Write a function named collatz() that has one parameter named number. If number is even, then collatz() should print number // 2 and return this value. If number is odd, then collatz() should print and return 3 * number + 1.
Then write a program that lets the user type in an integer and that keeps calling collatz() on that number until the function returns the value 1.
Remember to convert the return value from input() to an integer with the int() function; otherwise, it will be a string value.
Hint: An integer number is even if number % 2 == 0, and it’s odd if number % 2 == 1.
The output of this program could look something like this:
Enter number:
3
10
5
16
8
4
2
1
Input Validation
Add try and except statements to the previous project to detect whether the user types in a noninteger string. Normally, the int() function will raise a ValueError error if it is passed a noninteger string, as in int('puppy'). In the except clause, print a message to the user saying they must enter an integer.
# collatz.py: Collatz sequence
import sys
def collatz(number):
if number % 2 == 0:
print(number // 2)
return number // 2
else:
print(3 * number + 1)
return 3 * number + 1
print('Enter number:')
try:
inNumber = int(input())
except ValueError:
print('You must enter an integer.')
sys.exit()
while inNumber > 1:
inNumber = collatz(inNumber)
第4章（列表）練習(xí)項目：顯示列表內(nèi)容
Comma Code
Say you have a list value like this:
spam = ['apples', 'bananas', 'tofu', 'cats']
Write a function that takes a list value as an argument and returns a string with all the items separated by a comma and a space, with and inserted before the last item. For example, passing the previous spam list to the function would return 'apples, bananas, tofu, and cats'. But your function should be able to work with any list value passed to it.
# showList.py: Comma Code
def showList(inList):
outStr = ''
for i in range(len(inList)):
if i == 0:
outStr += inList[0]
elif i == len(inList) - 1:
outStr += ' and ' + inList[-1]
else:
outStr += ', ' + inList[i]
return outStr
spam = ['apples', 'bananas', 'tofu', 'cats']
print(showList(spam))
第4章（列表）練習(xí)項目2：字符圖案
Character Picture Grid
Say you have a list of lists where each value in the inner lists is a one-character string, like this:
grid = [['.', '.', '.', '.', '.', '.'],
['.', 'O', 'O', '.', '.', '.'],
['O', 'O', 'O', 'O', '.', '.'],
['O', 'O', 'O', 'O', 'O', '.'],
['.', 'O', 'O', 'O', 'O', 'O'],
['O', 'O', 'O', 'O', 'O', '.'],
['O', 'O', 'O', 'O', '.', '.'],
['.', 'O', 'O', '.', '.', '.'],
['.', '.', '.', '.', '.', '.']]
You can think of grid[x][y] as being the character at the x- and y-coordinates of a “picture” drawn with text characters. The (0, 0) origin will be in the upper-left corner, the x-coordinates increase going right, and w the y-coordinates increase going down.
Copy the previous grid value, and write code that uses it to print the image.
..OO.OO..
.OOOOOOO.
.OOOOOOO.
..OOOOO..
...OOO...
....O....
Hint: You will need to use a loop in a loop in order to print grid[0][0], then grid[1][0], then grid[2][0], and so on, up to grid[8][0]. This will finish the first row, so then print a newline. Then your program should print grid[0][1], then grid[1][1], then grid[2][1], and so on. The last thing your program will print is grid[8][5].
Also, remember to pass the end keyword argument to print() if you don’t want a newline printed automatically after each print() call.
# charPic.py: Character Picture Grid
grid = [['.', '.', '.', '.', '.', '.'],
['.', 'O', 'O', '.', '.', '.'],
['O', 'O', 'O', 'O', '.', '.'],
['O', 'O', 'O', 'O', 'O', '.'],
['.', 'O', 'O', 'O', 'O', 'O'],
['O', 'O', 'O', 'O', 'O', '.'],
['O', 'O', 'O', 'O', '.', '.'],
['.', 'O', 'O', '.', '.', '.'],
['.', '.', '.', '.', '.', '.']]
for y in range(len(grid[0])):
for x in range(len(grid)):
print(grid[x][y], end='')
print('\n')
第5章（字典）練習(xí)項目：游戲物品欄
Fantasy Game Inventory
You are creating a fantasy video game. The data structure to model the player’s inventory will be a dictionary where the keys are string values describing the item in the inventory and the value is an integer value detailing how many of that item the player has. For example, the dictionary value {'rope': 1, 'torch': 6, 'gold coin': 42, 'dagger': 1, 'arrow': 12} means the player has 1 rope, 6 torches, 42 gold coins, and so on.
Write a function named displayInventory() that would take any possible “inventory” and display it like the following:
Inventory:
12 arrow
42 gold coin
1 rope
6 torch
1 dagger
Total number of items: 63
Hint: You can use a for loop to loop through all the keys in a dictionary.
List to Dictionary Function for Fantasy Game Inventory
Imagine that a vanquished dragon’s loot is represented as a list of strings like this:
dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']
Write a function named addToInventory(inventory, addedItems), where the inventory parameter is a dictionary representing the player’s inventory (like in the previous project) and the addedItems parameter is a list like dragonLoot. The addToInventory() function should return a dictionary that represents the updated inventory. Note that the addedItems list can contain multiples of the same item. Your code could look something like this:
def addToInventory(inventory, addedItems):
# your code goes here
inv = {'gold coin': 42, 'rope': 1}
dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']
inv = addToInventory(inv, dragonLoot)
displayInventory(inv)
The previous program (with your displayInventory() function from the previous project) would output the following:
Inventory:
45 gold coin
1 rope
1 ruby
1 dagger
Total number of items: 48
# inventory.py: Fantasy Game Inventory
def displayInventory(inventory):
print("Inventory:")
item_total = 0
for k, v in inventory.items():
print(str(v) + ' ' + k)
item_total += v
print("Total number of items: " + str(item_total))
def addToInventory(inventory, addedItems):
# my code goes here
for i in addedItems:
inventory.setdefault(i, 0)
inventory[i] += 1
return inventory
inv = {'gold coin': 42, 'rope': 1}
dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']
inv = addToInventory(inv, dragonLoot)
displayInventory(inv)
第6章（操作字符串）練習(xí)項目：表格輸出
Table Printer
Write a function named printTable() that takes a list of lists of strings and displays it in a well-organized table with each column right-justified. Assume that all the inner lists will contain the same number of strings. For example, the value could look like this:
tableData = [['apples', 'oranges', 'cherries', 'banana'],
['Alice', 'Bob', 'Carol', 'David'],
['dogs', 'cats', 'moose', 'goose']]
Your printTable() function would print the following:
apples Alice dogs
oranges Bob cats
cherries Carol moose
banana David goose
Hint: Your code will first have to find the longest string in each of the inner lists so that the whole column can be wide enough to fit all the strings. You can store the maximum width of each column as a list of integers. The printTable() function can begin with colWidths = [0] * len(tableData), which will create a list containing the same number of 0 values as the number of inner lists in tableData. That way, colWidths[0] can store the width of the longest string in tableData[0], colWidths[1] can store the width of the longest string in tableData[1], and so on. You can then find the largest value in the colWidths list to find out what integer width to pass to the rjust() string method.
# tablePrinter.py: Table Printer
def printTable(inList):
colWidths = [0] * len(inList)
for x in range(len(inList)):
for i in inList[x]:
if colWidths[x] < len(i):
colWidths[x] = len(i)
for y in range(len(inList[0])):
for x in range(len(inList)):
print(inList[x][y].rjust(colWidths[x]), end=' ')
print('\n')
tableData = [['apples', 'oranges', 'cherries', 'banana'],
['Alice', 'Bob', 'Carol', 'David'],
['dogs', 'cats', 'moose', 'goose']]
printTable(tableData)
