MySQL練習(xí)題

SELECT * FROM course

SELECT * FROM score

SELECT * FROM teacher

SELECT * FROM student

1 查詢(xún)"01"課程比"02"課程成績(jī)高的學(xué)生的信息及課程分?jǐn)?shù)

第一步:查詢(xún)"01"課程的信息

SELECT * FROM score WHERE c_id ='01'

第二步: 查詢(xún)"02"課程的信息

SELECT * FROM score WHERE c_id='02'

第三步:? 查詢(xún)"01"課程比"02"課程成績(jī)高的學(xué)生號(hào)(左連接)

SELECT a.s_id

FROM

(SELECT * FROM score WHERE c_id ='01') AS a

LEFT JOIN

(SELECT * FROM score WHERE c_id='02') AS b

ON a.s_id=b.s_id

WHERE a.s_score>b.s_score OR b.s_id IS NULL

第四步:根據(jù)第三步的學(xué)生號(hào)查詢(xún)學(xué)生的信息及課程號(hào)钠龙、課程分?jǐn)?shù)

SELECT student.*,score.c_id,score.s_score

FROM student

JOIN score

ON student.s_id=score.s_id

WHERE student.s_id IN(SELECT a.s_id

FROM?(SELECT * FROM score WHERE c_id ='01') AS a

LEFT JOIN??(SELECT * FROM score WHERE c_id='02') AS b

ON a.s_id=b.s_id

WHERE a.s_score>b.s_score OR b.s_id IS NULL)


2查詢(xún)"01"課程比"02"課程成績(jī)低的學(xué)生的信息及課程分?jǐn)?shù)

第一步

SELECT * FROM student WHERE c_id='01'

第二步

SELECT * FROM student WHERE c_id='02'

第三步(右連接)

SELECT b.s_id

FROM (SELECT * FROM score WHERE c_id='01') AS a

RIGHT JOIN (SELECT * FROM score WHERE c_id='02') AS b

ON a.s_id =b.s_id

WHERE a.s_score<b.s_score OR a.s_id IS NULL

第四步

SELECT student.*,score.c_id,score.s_score

FROM student

JOIN score

ON student.s_id=score.s_id

WHERE student.s_id IN(SELECT b.s_id

FROM (SELECT * FROM score WHERE c_id='01') AS a

RIGHT JOIN (SELECT * FROM score WHERE c_id='02') AS b

ON a.s_id =b.s_id

WHERE a.s_score<b.s_score OR a.s_id IS NULL)


3平均成績(jī)大于等于60分的同學(xué)的學(xué)生編號(hào)和學(xué)生姓名和平均成績(jī)

內(nèi)連接

SELECT s.s_id,s.s_name,AVG(sc.s_score)

FROM student AS s

JOIN score AS sc

ON s.s_id = sc.s_id

GROUP BY s.s_id

HAVING AVG(sc.s_score)>=60


4查詢(xún)平均成績(jī)小于60分的同學(xué)的學(xué)生編號(hào)和學(xué)生姓名和平均成績(jī)

(包括有成績(jī)的和無(wú)成績(jī)的)

(左連接)

SELECT s.s_id,s.s_name,AVG(sc.s_score)

FROM student AS s

LEFT JOIN score AS sc

ON s.s_id=sc.s_id

GROUP BY s.s_id

HAVING AVG(sc.s_score)<60 OR AVG(sc.s_score) IS NULL


5所有同學(xué)的學(xué)生編號(hào)缩焦、學(xué)生姓名蓖康、選課總數(shù)、所有課程的總成績(jī)

SELECT s.s_id,s.s_name,COUNT(*) AS 選課總數(shù),SUM(sc.s_score) AS 總成績(jī)

FROM student AS s

JOIN score AS sc

ON s.s_id=sc.s_id

GROUP BY s.s_id


6查詢(xún)"李"姓老師的數(shù)量

SELECT COUNT(*) AS 數(shù)量

FROM teacher

WHERE t_name LIKE? '李%'


7查詢(xún)學(xué)過(guò)"張三"老師授課的同學(xué)的信息

第一步:找出學(xué)過(guò)“張三老師”的學(xué)生學(xué)號(hào)

SELECT sc.s_id

FROM score AS sc,teacher AS t,course AS c

WHERE sc.c_id=c.c_id

AND t.t_id=c.t_id

AND t.t_name='張三'

第二步

SELECT s.*

FROM student AS s

WHERE s.s_id IN

(SELECT sc.s_id

FROM score AS sc,teacher AS t,course AS c

WHERE sc.c_id=c.c_id

AND t.t_id=c.t_id

AND t.t_name='張三')


8查詢(xún)沒(méi)學(xué)過(guò)"張三"老師授課的同學(xué)的信息

第一步:找出學(xué)過(guò)“張三老師”的學(xué)生學(xué)號(hào)

SELECT sc.s_id

FROM score AS sc,teacher AS t,course AS c

WHERE sc.c_id=c.c_id

AND t.t_id=c.t_id

AND t.t_name='張三'

第二步

SELECT s.*

FROM student AS s

WHERE s.s_id NOT IN

(SELECT sc.s_id

FROM score AS sc,teacher AS t,course AS c

WHERE sc.c_id=c.c_id

AND t.t_id=c.t_id

AND t.t_name='張三')


9學(xué)過(guò)編號(hào)為"01"并且也學(xué)過(guò)編號(hào)為"02"的課程的同學(xué)的信息

第一種寫(xiě)法

第一步

SELECT s_id FROM score WHERE c_id='01'

第二步

SELECT s_id FROM score WHERE c_id='02'

第三步

SELECT a.s_id

FROM (SELECT s_id FROM score WHERE c_id='01') AS a

JOIN (SELECT s_id FROM score WHERE c_id='02') AS b

ON a.s_id=b.s_id

第四步

SELECT student.*

FROM student

WHERE s_id IN(SELECT a.s_id

FROM (SELECT s_id FROM score WHERE c_id='01') AS a

JOIN (SELECT s_id FROM score WHERE c_id='02') AS b

ON a.s_id=b.s_id)

第二種寫(xiě)法

SELECT s.*

FROM student AS s,

(SELECT score.s_id

FROM score

WHERE score.c_id='01') AS a,

(SELECT score.s_id

FROM score

WHERE score.c_id='02') AS b

WHERE s.s_id=a.s_id

AND s.s_id=b.s_id


10學(xué)過(guò)編號(hào)為"01"但是沒(méi)有學(xué)過(guò)編號(hào)為"02"的課程的同學(xué)的信息

第一步

SELECT s_id FROM score WHERE c_id='01'

第二步

SELECT s_id FROM score WHERE c_id='02'

第三步:(左連接,找出學(xué)過(guò)‘01’但沒(méi)有學(xué)過(guò)‘02’的學(xué)生編號(hào))

SELECT a.s_id

FROM (SELECT s_id FROM score WHERE c_id='01') AS a

LEFT JOIN (SELECT s_id FROM score WHERE c_id='02') AS b

ON a.s_id=b.s_id

WHERE b.s_id IS NULL

第四步

SELECT student.*

FROM student

WHERE s_id IN(SELECT a.s_id

FROM (SELECT s_id FROM score WHERE c_id='01') AS a

LEFT JOIN (SELECT s_id FROM score WHERE c_id='02') AS b

ON a.s_id=b.s_id

WHERE b.s_id IS NULL)


11查詢(xún)沒(méi)有學(xué)全所有課程的同學(xué)的信息

第一步

SELECT s_id

FROM score

GROUP BY s_id

HAVING COUNT(*)!=(SELECT COUNT(DISTINCT c_id) FROM course)

第二步

SELECT student.*

FROM student

WHERE s_id IN(SELECT s_id

FROM score

GROUP BY s_id

HAVING COUNT(*)!=(SELECT COUNT(DISTINCT c_id)? ?FROM course))


12查詢(xún)至少有一門(mén)課與學(xué)號(hào)為"01"的同學(xué)所學(xué)相同的同學(xué)的信息

第一步

SELECT c_id

FROM score

WHERE s_id='01'

第二步

SELECT student.*

FROM student

JOIN score

ON student.s_id=score.s_id

WHERE score.c_id IN (SELECT c_id? ?FROM score??WHERE s_id='01')

AND student.s_id !='01'

GROUP BY student.s_id


13查詢(xún)和"01"號(hào)的同學(xué)學(xué)習(xí)的課程完全相同的其他同學(xué)的信息

SELECT *

FROM student

JOIN score

WHERE student.s_id=score.s_id

GROUP BY student.s_id

HAVING score.c_id IN (SELECT c_id? ?FROM score? ?WHERE s_id='01')

AND student.s_id !='01'

AND COUNT(score.c_id)=(SELECT COUNT(score.c_id) FROM score WHERE s_id='01')


14查詢(xún)沒(méi)學(xué)過(guò)"張三"老師講授的任一門(mén)課程的學(xué)生姓名

第一步

SELECT sc.s_id

FROM teacher AS t,course AS c,score AS sc

WHERE t.t_id=c.t_id

AND sc.c_id=c.c_id

AND t.t_name='張三'

第二步

SELECT student.*

FROM student

WHERE student.s_id NOT IN

(SELECT sc.s_id

FROM teacher AS t,course AS c,score AS sc

WHERE t.t_id=c.t_id

AND sc.c_id=c.c_id

AND t.t_name='張三')


15查詢(xún)兩門(mén)及其以上不及格課程的同學(xué)的學(xué)號(hào)呀伙,姓名及其平均成績(jī)

第一步

SELECT s_id

FROM score

WHERE s_score<60

GROUP BY s_id

HAVING COUNT(*)>=2

第二步

SELECT s.s_id,s.s_name,AVG(sc.s_score)

FROM student AS s

JOIN score AS sc

ON s.s_id=sc.s_id

GROUP BY s.s_id

HAVING s.s_id IN

(SELECT s_id

FROM score

WHERE s_score<60

GROUP BY s_id

HAVING COUNT(*)>=2)


16檢索"01"課程分?jǐn)?shù)小于60,按分?jǐn)?shù)降序排列的學(xué)生信息

SELECT? student.*

FROM student

JOIN score

ON student.s_id=score.s_id

WHERE score.c_id='01'

AND score.s_score<60

ORDER BY score.s_score DESC


17按平均成績(jī)從高到低顯示所有學(xué)生的所有課程的成績(jī)以及平均成績(jī)

SELECT s_id AS sid,

(SELECT s_score FROM score WHERE s_id=sid AND c_id='01') AS 語(yǔ)文,

(SELECT s_score FROM score WHERE s_id=sid AND c_id='02') AS 數(shù)學(xué),

(SELECT s_score FROM score WHERE s_id=sid AND c_id='03') AS 英語(yǔ),

AVG(s_score) AS 平均成績(jī)

FROM score

GROUP BY s_id

ORDER BY 平均成績(jī) DESC


18.查詢(xún)各科成績(jī)最高分、最低分和平均分:以如下形式顯示:課程ID日丹,課程name,最高分蚯嫌,最低分哲虾,平均分,及格率择示,中等率束凑,優(yōu)良率,優(yōu)秀率

SELECT

sc.c_id,

c.c_name,

MAX(s_score) AS 最高分,

MIN(s_score) AS 最低分,

AVG(s_score) AS 平均分,

SUM(CASE WHEN s_score>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格率,

SUM(CASE WHEN s_score>=70 AND s_score<80 THEN 1 ELSE 0 END)/COUNT(*) AS 中等率,

SUM(CASE WHEN s_score>=80 AND s_Score<90 THEN 1 ELSE 0 END)/COUNT(*) AS 優(yōu)良率,

SUM(CASE WHEN s_score>90 THEN 1 ELSE 0 END)/COUNT(*) AS 優(yōu)秀率

FROM score AS sc

JOIN course AS c

ON sc.c_id=c.c_id

GROUP BY sc.c_id


19按各科成績(jī)進(jìn)行排序栅盲,并顯示排名(實(shí)現(xiàn)不完全)


20查詢(xún)學(xué)生的總成績(jī)并進(jìn)行排名


21查詢(xún)不同老師所教不同課程平均分從高到低顯示

SELECT t.t_id, c.c_id,AVG(sc.s_score) AS 平均成績(jī)

FROM score AS sc,teacher AS t,course AS c

WHERE sc.c_id=c.c_id

AND t.t_id=c.t_id

GROUP BY t.t_id,c.c_id

ORDER BY 平均成績(jī) DESC


22查詢(xún)所有課程的成績(jī)第2名到第3名的學(xué)生信息及該課程成績(jī)

23統(tǒng)計(jì)各科成績(jī)各分?jǐn)?shù)段人數(shù),課程編號(hào),課程名稱(chēng),[100-85],[85-70],[70-60],[0-60]及所占百分比

SELECT COUNT(*),

? ? ? c.c_id,

? ? ? c.c_name,

? ? ? SUM(CASE WHEN sc.s_score>=85 AND sc.s_score<=100 THEN 1 ELSE 0 END)/COUNT(*) AS '[85-100]',

? ? ? SUM(CASE WHEN sc.s_score>=70 AND sc.s_score<85 THEN 1 ELSE 0 END)/COUNT(*)? AS '[85-70]',

? ? ? SUM(CASE WHEN sc.s_score>=60 AND sc.s_score<70 THEN 1 ELSE 0 END)/COUNT(*) AS '[70-60]',

? ? ? SUM(CASE WHEN sc.s_score>=0 AND sc.s_score<60 THEN 1 ELSE 0 END)/COUNT(*) AS '[0-60]'

FROM score AS sc

JOIN course c

ON c.c_id=sc.c_id

GROUP BY c.c_id


24查詢(xún)學(xué)生平均成績(jī)及其名次


25查詢(xún)各科成績(jī)前三名的記錄

SELECT c_id AS cid,

(SELECT s_score FROM score WHERE c_id =cid ORDER BY s_score DESC? LIMIT 1) AS 第一名,

(SELECT s_score FROM score WHERE c_id =cid ORDER BY s_score DESC LIMIT 1,1) AS 第二名,

(SELECT s_score FROM score WHERE c_id =cid ORDER BY s_score DESC LIMIT 2,1) AS 第三名

FROM score

GROUP BY cid


26查詢(xún)每門(mén)課程被選修的學(xué)生數(shù)

SELECT c_id,COUNT(*) AS 人數(shù)

FROM score

GROUP BY c_id


27查詢(xún)出只有兩門(mén)課程的全部學(xué)生的學(xué)號(hào)和姓名

SELECT s.s_id,s.s_name

FROM student AS s

JOIN score AS sc

ON s.s_id=sc.s_id

GROUP BY s.s_id

HAVING COUNT(*)=2


28查詢(xún)男生汪诉、女生人數(shù)

SELECT s_sex,COUNT(*)

FROM student

GROUP BY s_sex


29查詢(xún)名字中含有"風(fēng)"字的學(xué)生信息

SELECT *

FROM student

WHERE s_name LIKE '%風(fēng)%'


30查詢(xún)同名同性學(xué)生名單,并統(tǒng)計(jì)同名人數(shù)

SELECT a.s_name,a.s_sex,COUNT(*) AS 同名人數(shù)

FROM student AS a

JOIN student AS b

ON a.s_id !=b.s_id

AND a.s_name=b.s_name

AND a.s_sex=b.s_sex

GROUP BY a.s_name


31查詢(xún)1990年出生的學(xué)生名單

第一種表達(dá)方式:

SELECT student.*

FROM student

WHERE YEAR(s_birth)=1990

第二種表達(dá)方式 :? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ??

select student.*

FROM student

WHERE DATE_FORMAT(s_birth,'%Y')=1990


32查詢(xún)每門(mén)課程的平均成績(jī)剪菱,結(jié)果按平均成績(jī)降序排列摩瞎,平均成績(jī)相同時(shí),按課程編號(hào)升序排列

SELECT c_id, AVG(s_score)

FROM score

GROUP BY c_id

ORDER BY AVG(s_score) DESC,c_id ASC


33查詢(xún)平均成績(jī)大于等于85的所有學(xué)生的學(xué)號(hào)孝常、姓名和平均成績(jī)

SELECT s.s_id,s.s_name,AVG(sc.s_score)

FROM student AS s

JOIN score AS sc

ON s.s_id=sc.s_id

GROUP BY s.s_id

HAVING AVG(sc.s_score)>=85


34查詢(xún)課程名稱(chēng)為"數(shù)學(xué)"旗们,且分?jǐn)?shù)低于60的學(xué)生姓名和分?jǐn)?shù)

SELECT s.s_name,sc.s_score

FROM student AS s

JOIN score AS sc

ON s.s_id=sc.s_id

JOIN course AS c

ON c.c_id=sc.c_id

WHERE c.c_name='數(shù)學(xué)'

AND sc.s_score<60


35查詢(xún)所有學(xué)生的課程及分?jǐn)?shù)情況

SELECT student.s_id AS sid,

? ? ? student.s_name,

(SELECT s_score FROM score WHERE s_id=sid AND c_id='01') AS 語(yǔ)文,

(SELECT s_score FROM score WHERE s_id=sid AND c_id='02') AS 數(shù)學(xué),

(SELECT s_score FROM score WHERE s_id=sid AND c_id='03') AS 英語(yǔ)

FROM student

JOIN score

ON student.s_id=score.s_id

GROUP BY student.s_id


36查詢(xún)?nèi)魏我婚T(mén)課程成績(jī)?cè)?0分以上的姓名、課程名稱(chēng)和分?jǐn)?shù)构灸;

SELECT s.s_name,c.c_name,sc.s_score

FROM student AS s

JOIN score AS sc

ON s.s_id =sc.s_id

JOIN course AS c

ON c.c_id=sc.c_id

WHERE sc.s_score>70


37查詢(xún)不及格的課程

SELECT s.s_name, c.c_name, sc.s_score

FROM score AS sc

JOIN course AS c

ON sc.c_id=c.c_id

JOIN student AS s

ON sc.s_id=s.s_id

WHERE sc.s_score<60


38查詢(xún)課程編號(hào)為01且課程成績(jī)?cè)?0分以上的學(xué)生的學(xué)號(hào)和姓名

SELECT s.s_id,s.s_name

FROM student AS s

JOIN score AS sc

ON s.s_id=sc.s_id

WHERE sc.c_id='01'

AND sc.s_score>80


39求每門(mén)課程的學(xué)生人數(shù)

SELECT c_id,COUNT(*) AS 學(xué)生人數(shù)

FROM score

GROUP BY c_id


40查詢(xún)選修"張三"老師所授課程的學(xué)生中上渴,成績(jī)最高的學(xué)生信息及其成績(jī)

SELECT student.*,MAX(score.s_score)

FROM student

JOIN score

ON student.s_id=score.s_id

WHERE student.s_id IN(SELECT sc.s_id

FROM course AS c

JOIN teacher AS t

ON c.t_id=t.t_id

JOIN score AS sc

ON c.c_id=sc.c_id

WHERE t.t_name='張三')


41查詢(xún)不同課程成績(jī)相同的學(xué)生的學(xué)生編號(hào)岸梨、課程編號(hào)、學(xué)生成績(jī)

SELECT DISTINCT a.s_id,a.c_id,a.s_score

FROM score AS a

JOIN score AS b

ON a.s_id=b.s_id

WHERE a.c_id!=b.c_id

AND a.s_score=b.s_score


42查詢(xún)每門(mén)功成績(jī)最好的前兩名

SELECT c_id AS cid,

(SELECT s_score FROM score WHERE c_id=cid ORDER BY s_score DESC LIMIT 1) AS 第一名,

(SELECT s_score FROM score WHERE c_id=cid ORDER BY s_score DESC LIMIT 1,1) AS 第二名

FROM score

GROUP BY c_id


43統(tǒng)計(jì)每門(mén)課程的學(xué)生選修人數(shù)(超過(guò)5人的課程才統(tǒng)計(jì))

要求輸出課程號(hào)和選修人數(shù)稠氮,查詢(xún)結(jié)果按人數(shù)降序排列

若人數(shù)相同曹阔,按課程號(hào)升序排列

SELECT c_id,COUNT(*) AS 選修人數(shù)

FROM score

GROUP BY c_id

HAVING COUNT(*)>5

ORDER BY 選修人數(shù) DESC,c_id ASC


44檢索至少選修兩門(mén)課程的學(xué)生學(xué)號(hào)

SELECT s_id

FROM score

GROUP BY s_id

HAVING COUNT(*)>=2


45查詢(xún)選修了全部課程的學(xué)生信息

SELECT student.*

FROM student

JOIN score

ON student.s_id=score.s_id

GROUP BY student.s_id

HAVING COUNT(*)=(SELECT COUNT(DISTINCT c_id)

? ? ? ? ? ? ? ? FROM course)


46查詢(xún)各學(xué)生的年齡

按照出生日期來(lái)算,當(dāng)前月日 < 出生年月的月日則隔披,年齡減一

SELECT s_name,s_birth,

(DATE_FORMAT(NOW(),'%Y')-DATE_FORMAT(s_birth,'%Y')-

(CASE WHEN DATE_FORMAT(NOW(),'%m%d')<DATE_FORMAT(s_birth,'%m%d') THEN 1 ELSE 0 END))? AS 年齡

FROM student


47查詢(xún)本周過(guò)生日的學(xué)生

SELECT student.*

FROM student

WHERE WEEK(s_birth,1)=WEEK(CURDATE(),1)

SELECT DATE(NOW())

SELECT CURDATE()


48查詢(xún)下周過(guò)生日的學(xué)生

SELECT student.*

FROM student

WHERE WEEK(s_birth,1)=WEEK(CURDATE(),1)+1


49查詢(xún)本月過(guò)生日的學(xué)生

SELECT student.*

FROM student

WHERE MONTH(s_birth)=MONTH(CURDATE())


50查詢(xún)下月過(guò)生日的學(xué)生

SELECT student.*

FROM student

WHERE DATE_FORMAT(s_birth,'%m')=DATE_FORMAT(NOW(),'%m')+1

SELECT student.*

FROM student

WHERE MONTH(s_birth)=MONTH(CURDATE())+1

SELECT(NOW())

SELECT(DATE(NOW()))

SELECT(YEAR(NOW()))

SELECT(MONTH(NOW()))

SELECT(DAY(NOW()))

SELECT(TIME(NOW()))

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