1. 有N個人圍成一圈诺凡，順序排號沸柔，從第一個人開始報數(shù)暑刃，凡是報到M的人退出圈子勤讽，問最后留下的幾號?

#define N 15
int main(int argc, char const *argv[])
{
    int M;
    scanf("%d",&M);

    int people[N]={0};
    int people_remain = N;
    int people_out = 0;
    int people_count = 1;
    int i = 0;
    while(people_remain!=1){
        if (0 == people[i]){
            if(M == people_count){
                people[i] = 1;
                --people_remain;
                ++people_out;
                people_count=1;
            }
            else
                ++people_count;
        }
        i=(i+1)%N;
    }
    for (int i = 0; i < N; ++i)
    {
        if (people[i] == 0)
            printf("%d\n",i+1);
    }
    return 0;
}

2. N個人圍成一圈蟋座，從第S個人開始順時針1,2,3,4,...M的順序報數(shù)，數(shù)到M的人出圈脚牍，然后從出圈的下一個人開始重復(fù)此過程向臀，輸出所有出圈的人的順序。

int main(int argc, char const *argv[])
{
    int M,S,N;
    printf("please input people number\n");
    scanf("%d",&N);//總?cè)藬?shù)

    printf("please input counting cycle\n");
    scanf("%d",&M);//報數(shù)循環(huán)

    printf("please input counting start people\n");
    scanf("%d",&S);//從第幾個人開始

    int *people =(int *)calloc(N,sizeof(int));
    int people_remain = N;
    int people_out = 0;
    int people_count = 1;
    int i = S-1;

    printf("出圈人的順序為：");
    while(people_remain!=1)
    {
        if (0 == people[i])
        {
            if(M == people_count)
            {
                printf("%d,",i+1);
                people[i] = 1;
                --people_remain;
                ++people_out;
                people_count=1;
            }
            else
                ++people_count;
        }
        i=(i+1)%N;
    }
    printf("\n");
    for (int i = 0; i < N; ++i)
    {
        if (people[i] == 0)
            printf("%d\n",i+1);
    }
    return 0;
}

** N個人圍成一圈诸狭，從第1個人開始順時針1,2,3,4,...M的順序報數(shù)券膀，數(shù)到M的人出圈，然后從出圈的下一個人開始重復(fù)此過程,直到圈中所剩的人數(shù)為M-1個人驯遇。輸出所有出圈的人的順序,并輸出剩余的人的編號**

int main(int argc, char const *argv[])
{
    int M,N;
    printf("please input people number\n");
    scanf("%d",&N);

    printf("please input counting cycle\n");
    scanf("%d",&M);

    int *people =(int *)calloc(N,sizeof(int));
    int people_remain = N;
    int people_count = 1;
    int i = 0;
    printf("出圈人的順序為：");
    while(people_remain!=M-1)
    {
        if (0 == people[i])
        {
            if(M == people_count)
            {
                printf("%d,",i+1);
                people[i] = 1;
                --people_remain;
                people_count=1;
            }
            else
                ++people_count;
        }
        i=(i+1)%N;
    }
    printf("\n");

    printf("剩下的人的編號為:");
    for (int i = 0; i < N; ++i)
    {
        if (people[i] == 0)
            printf("%d,",i+1);
    }
    printf("\n");
    return 0;
}