高德地圖搜索poi的api介紹地址

當前想法是爬取目標區(qū)域（作者所在小縣城）的所有poi數(shù)據(jù)，存到數(shù)據(jù)庫中作為原始數(shù)據(jù)，然后供其它系統(tǒng)調用途茫，因為之前爬取過百度地圖的poi數(shù)據(jù)桌吃，所以這次工作就駕輕就熟了娜睛。

1哆键、首先注冊一個高德地圖的開發(fā)者賬號掘托，申請一個綁定Web服務的key，然后把剛注冊的開發(fā)者賬號認證一下： 申請賬號洼哎、key就不贅述了烫映，去高德地圖開發(fā)平臺很簡單就能完成了，將賬號認證是為了提高每日訪問高德地圖api接口的次數(shù)限制和并發(fā)請求噩峦。

2、根據(jù)上方api地址里面的介紹抽兆，總共分為4中搜索： 關鍵字搜索：通過用POI的關鍵字進行條件搜索识补，例如：肯德基、朝陽公園等辫红；同時支持設置POI類型搜索凭涂，例如：銀行 周邊搜索：在用戶傳入經緯度坐標點附近，在設定的范圍內贴妻，按照關鍵字或POI類型搜索切油； 多邊形搜索：在多邊形區(qū)域內進行搜索 ID查詢：通過POI ID，查詢某個POI詳情名惩，建議可同輸入提示API配合使用

我的目標是某個區(qū)域的所有poi澎胡，所以選擇的第三種：多邊形搜索

3、多邊形搜索最重要的參數(shù)就是polygon-》經緯度坐標對娩鹉，我在百度地圖坐標拾取系統(tǒng)拾取了我的目標區(qū)域的經緯度坐標對攻谁，如下圖：?

3步準備工作到這里就差不多結束了，在正式開始碼代碼之前先做個測試吧弯予，用瀏覽器直接訪問接口看看返回的數(shù)據(jù)（當然戚宦，高德的api接口有返回數(shù)據(jù)說明）

如上圖，這里比較重要的一個屬性是count锈嫩，根據(jù)api的介紹count是搜索方案數(shù)目(最大值為1000)受楼，所以說每次請求都會返回當前所搜所包含的poi個數(shù)，而大于1000的poi是沒有辦法獲取到的呼寸。那么我如果想查詢某個區(qū)域的全部數(shù)據(jù)艳汽，可以將這個區(qū)域再劃分成更小的區(qū)域（顯然是個遞歸操作）的集合，然后把這幾個可以查到所有poi的區(qū)域的所有poi數(shù)據(jù)結合起來就是我最終需要的數(shù)據(jù)等舔∩Ь模可能口述不明朗，可以見下方草圖：

如果需要Python方面的入門知識可以點擊這個鏈接獲取入門資料

好慌植，可以開始擼代碼了：

因為甚牲，整個調用API的過程都離不開經緯度义郑，所以首先定義一個經緯度描述的類 `

//矩形塊的經緯度標識， 左上角的經緯度 和右下角的經緯度classRectangleCoordinate{/**

? ? * 矩形左上角經度

? ? */privatedoublex0;/**

? ? * 矩形左上角緯度

? ? */privatedoubley0;/**

? ? * 矩形右下角經度

? ? */privatedoublex1;/**

? ? * 矩形右下角緯度

? ? */privatedoubley1;publicRectangleCoordinate(doublex0,doubley0,doublex1,doubley1){this.x0 = x0;this.y0 = y0;this.x1 = x1;this.y1 = y1;? ? }/**

? ? * [@return](https://my.oschina.net/u/556800) 獲取矩形中心線的緯度

? ? */publicdoublegetAverageY(){return(y0 + y1) /2;? ? }/**

? ? * [@return](https://my.oschina.net/u/556800) 獲取矩形中心線的經度

? ? */publicdoublegetAverageX(){return(x0 + x1) /2;? ? }publicdoublegetX0(){returnx0;? ? }publicvoidsetX0(doublex0){this.x0 = x0;? ? }publicdoublegetY0(){returny0;? ? }publicvoidsetY0(doubley0){this.y0 = y0;? ? }publicdoublegetX1(){returnx1;? ? }publicvoidsetX1(doublex1){this.x1 = x1;? ? }publicdoublegetY1(){returny1;? ? }publicvoidsetY1(doubley1){this.y1 = y1;? ? }? ? [@Override](https://my.oschina.net/u/1162528)publicStringtoString(){returnx0 +","+ y0 +"|"+ x1 +","+ y1;? ? }}`

然后需要一個調用api丈钙，獲取返回數(shù)據(jù)的方法非驮，這個方法參數(shù)就是矩形塊，當然還需要一個頁數(shù)雏赦，即當前方法獲取的是某個矩形區(qū)域的第X頁的數(shù)據(jù)（每頁上線25個poi劫笙，默認20個poi）

/**? ? *@return獲取矩形塊的poi數(shù)據(jù)? ? */privateJSONObjectgetSearchResult(RectangleCoordinate coordinate,intpage){? ? ? ? RestTemplate restTemplate =newRestTemplate();? ? ? ? String url = getRequestGaodeUrl(coordinate,page);? ? ? ? String result = restTemplate.getForObject(url, String.class);try{try{? ? ? ? ? ? ? ? Thread.sleep(50);? ? ? ? ? ? }catch(InterruptedException e) {? ? ? ? ? ? ? ? e.printStackTrace();? ? ? ? ? ? }returnJSONObject.parseObject(result);? ? ? ? }catch(Exception e) {? ? ? ? ? ? logger.error("an error occurred when getting response of gaode map data for coordinate:[{}]", coordinate.toString());? ? ? ? }returnnull;? ? }

當然，上方已經說過星岗，如果矩形塊返回數(shù)據(jù)count=1000填大，就說明當前矩形塊需要分割，我的想法比較簡單俏橘，將矩形塊按照上方草圖允华，在水平中心和垂直分心分割，1個矩形塊就分割成4個小矩形塊了寥掐，方法如下：

/**? ? *@return將矩形4等分成小矩形 然后返回4個 小矩形的經緯度集合? ? */privateListgetSplitRectangleList(RectangleCoordinate coordinate){? ? ? ? List splitRectangleList =newLinkedList<>();? ? ? ? splitRectangleList.add(newRectangleCoordinate(coordinate.getX0(), coordinate.getY0(), coordinate.getAverageX(), coordinate.getAverageY()));? ? ? ? splitRectangleList.add(newRectangleCoordinate(coordinate.getAverageX(), coordinate.getY0(), coordinate.getX1(), coordinate.getAverageY()));? ? ? ? splitRectangleList.add(newRectangleCoordinate(coordinate.getX0(), coordinate.getAverageY(), coordinate.getAverageX(), coordinate.getY1()));? ? ? ? splitRectangleList.add(newRectangleCoordinate(coordinate.getAverageX(), coordinate.getAverageY(), coordinate.getX1(), coordinate.getY1()));returnsplitRectangleList;? ? }

目前靴寂，可以獲取到矩形區(qū)域經緯度對的集合了，也有獲取api數(shù)據(jù)的方法了召耘，然后就是遍歷頁數(shù)獲取數(shù)據(jù)百炬，自定義操作數(shù)據(jù)。 當某次分頁請求返回的poi個數(shù)小于每頁最大個數(shù)的時候就認為當前區(qū)域poi已經完全請求到了污它。

privatevoidstartAnaMainGaode(RectangleCoordinate coordinate)throwsAnalysisException{//當前爬取的數(shù)據(jù)的頁數(shù)索引intpage_num =0;//當前爬取內容是否是最后一頁booleanisLastPage =false;? ? ? ? JSONObject searchResult;? ? ? ? JSONArray datas =null;? ? ? ? logger.info("ready to analysis coordinate:[{}]", coordinate.toString());while(!isLastPage) {? ? ? ? ? ? logger.info("is going to get data for page_"+ page_num);try{? ? ? ? ? ? ? ? searchResult = getSearchResult(coordinate, page_num);? ? ? ? ? ? ? ? datas = searchResult.getJSONArray("pois");? ? ? ? ? ? }catch(Exception e) {? ? ? ? ? ? ? ? logger.error("an error occurred when getting response of gaode map data for coordinate:[{}]", coordinate.toString());? ? ? ? ? ? }if(datas !=null&& datas.size() <20) {? ? ? ? ? ? ? ? isLastPage =true;? ? ? ? ? ? ? ? logger.info("get result counts is [{}], now page index is [{}]", datas.size(), page_num);? ? ? ? ? ? }? ? ? ? ? ? saveIntoDbGaode(datas);? ? ? ? ? ? page_num++;? ? ? ? }? ? }

privatevoidsaveIntoDbGaode(JSONArray result){? ? JSONObject resultItem;for(inti =0; i < result.size(); i++) {? ? ? ? resultItem = result.getJSONObject(i);try{? ? ? ? ? ? results.add(getInsertUnitObject(resultItem));? ? ? ? }catch(Exception e) {? ? ? ? ? ? logger.error("生成數(shù)據(jù)時異常剖踊，e: {}", e.getMessage());? ? ? ? ? ? e.printStackTrace();? ? ? ? }? ? }if(results.size() > BATCHINSERTLIMIT || ISLAST) {? ? ? ? logger.info("is ready to batch insert into unit, total count is {}", results.size());try{? ? ? ? ? ? dao.batchAddUnitGaode(results);? ? ? ? }catch(Exception e) {? ? ? ? ? ? logger.error("更新數(shù)據(jù)庫異常，e: {}", e.getMessage());? ? ? ? }? ? ? ? results =newJSONArray();? ? }}`

到此轨蛤，基本方法都介紹過了蜜宪，全部代碼如下（因為都是簡單方法和邏輯，不明白的留言交流）

//請求入口 publicvoidGaodePoiSearch(){//徐水區(qū) final RectangleCoordinate searchAreaCoordinate = new RectangleCoordinate(115.521773, 39.106335, 115.801182, 38.943988);? ? //保定市//final RectangleCoordinate searchAreaCoordinate = new RectangleCoordinate(114.332719,39.574064, 116.588688,38.179144);List validCoordinate = getValidCoordinate(searchAreaCoordinate);? ? logger.info("get all valid coordinate,size is [{}]", validCoordinate.size());/**

? ? * 獲取到所有的小方塊之后可以做一些處理祥山， 比如存儲到某個地方圃验，以防發(fā)生異常，方便后面重新遍歷缝呕，我這里暫未做處理

? ? */validCoordinate.forEach(coor -> {try{? ? ? ? ? ? startAnaMainGaode(coor);? ? ? ? }catch(AnalysisException e) {? ? ? ? ? ? e.printStackTrace();? ? ? ? }? ? });? ? ISLAST =true;? ? saveIntoDbGaode(newJSONArray());}/** * [@return](https://my.oschina.net/u/556800) 獲取矩形塊中 符合 調用api的 小矩形塊的集合 * 因為高德地圖某個矩形塊只能獲取前1000條澳窑，所以要將矩形塊分割成可以獲取到全部數(shù)據(jù)的矩形塊 * 如果當前矩形塊請求數(shù)據(jù)返回的count<1000 即為符合條件的，否則將矩形塊4等分 然后遞歸 */privateListgetValidCoordinate(RectangleCoordinate coordinate){? ? List validCoordinate =newLinkedList<>();? ? JSONObject searchResult = getSearchResult(coordinate,0);if(searchResult.getIntValue("count") >=1000) {? ? ? ? List splitRectangleList = getSplitRectangleList(coordinate);? ? ? ? splitRectangleList.forEach(coor -> validCoordinate.addAll(getValidCoordinate(coor)));? ? }else{? ? ? ? logger.info("add a valid coordinate [{}]", coordinate.toString());? ? ? ? validCoordinate.add(coordinate);? ? }returnvalidCoordinate;}/** * [@return](https://my.oschina.net/u/556800) 將矩形4等分成小矩形 然后返回4個 小矩形的經緯度集合 */privateListgetSplitRectangleList(RectangleCoordinate coordinate){? ? List splitRectangleList =newLinkedList<>();? ? splitRectangleList.add(newRectangleCoordinate(coordinate.getX0(), coordinate.getY0(), coordinate.getAverageX(), coordinate.getAverageY()));? ? splitRectangleList.add(newRectangleCoordinate(coordinate.getAverageX(), coordinate.getY0(), coordinate.getX1(), coordinate.getAverageY()));? ? splitRectangleList.add(newRectangleCoordinate(coordinate.getX0(), coordinate.getAverageY(), coordinate.getAverageX(), coordinate.getY1()));? ? splitRectangleList.add(newRectangleCoordinate(coordinate.getAverageX(), coordinate.getAverageY(), coordinate.getX1(), coordinate.getY1()));returnsplitRectangleList;}/** *@return獲取矩形塊的poi數(shù)據(jù) */privateJSONObjectgetSearchResult(RectangleCoordinate coordinate,intpage){? ? RestTemplate restTemplate =newRestTemplate();? ? String url = getRequestGaodeUrl(coordinate,page);? ? String result = restTemplate.getForObject(url, String.class);try{try{? ? ? ? ? ? Thread.sleep(50);? ? ? ? }catch(InterruptedException e) {? ? ? ? ? ? e.printStackTrace();? ? ? ? }returnJSONObject.parseObject(result);? ? }catch(Exception e) {? ? ? ? logger.error("an error occurred when getting response of gaode map data for coordinate:[{}]", coordinate.toString());? ? }returnnull;}privatevoidstartAnaMainGaode(RectangleCoordinate coordinate)throwsAnalysisException{//當前爬取的數(shù)據(jù)的頁數(shù)索引intpage_num =0;//當前爬取內容是否是最后一頁booleanisLastPage =false;? ? JSONObject searchResult;? ? JSONArray datas =null;? ? logger.info("ready to analysis coordinate:[{}]", coordinate.toString());while(!isLastPage) {? ? ? ? logger.info("is going to get data for page_"+ page_num);try{? ? ? ? ? ? searchResult = getSearchResult(coordinate, page_num);? ? ? ? ? ? datas = searchResult.getJSONArray("pois");? ? ? ? }catch(Exception e) {? ? ? ? ? ? logger.error("an error occurred when getting response of gaode map data for coordinate:[{}]", coordinate.toString());? ? ? ? }if(datas !=null&& datas.size() <20) {? ? ? ? ? ? isLastPage =true;? ? ? ? ? ? logger.info("get result counts is [{}], now page index is [{}]", datas.size(), page_num);? ? ? ? }? ? ? ? saveIntoDbGaode(datas);? ? ? ? page_num++;? ? }}privatevoidsaveIntoDbGaode(JSONArray result){? ? JSONObject resultItem;for(inti =0; i < result.size(); i++) {? ? ? ? resultItem = result.getJSONObject(i);try{? ? ? ? ? ? results.add(getInsertUnitObject(resultItem));? ? ? ? }catch(Exception e) {? ? ? ? ? ? logger.error("生成數(shù)據(jù)時異常供常，e: {}", e.getMessage());? ? ? ? ? ? e.printStackTrace();? ? ? ? }? ? }if(results.size() > BATCHINSERTLIMIT || ISLAST) {? ? ? ? logger.info("is ready to batch insert into unit, total count is {}", results.size());try{? ? ? ? ? ? dao.batchAddUnitGaode(results);? ? ? ? }catch(Exception e) {? ? ? ? ? ? logger.error("更新數(shù)據(jù)庫異常摊聋，e: {}", e.getMessage());? ? ? ? }? ? ? ? results =newJSONArray();? ? }}privateJSONObjectgetInsertUnitObject(JSONObject resultItem){? ? JSONObject unitDataObject =newJSONObject();? ? unitDataObject.put("uid", resultItem.getString("id"));? ? unitDataObject.put("name", resultItem.getString("name"));? ? unitDataObject.put("type", resultItem.getString("type"));? ? unitDataObject.put("tag", resultItem.getString("type"));? ? unitDataObject.put("address", resultItem.getString("address"));? ? unitDataObject.put("province", resultItem.getString("pname"));? ? unitDataObject.put("city", resultItem.getString("cityname"));? ? unitDataObject.put("area", resultItem.getString("adname"));? ? String tel = resultItem.getString("tel");if(tel !=null&& !"[]".equals(tel)) {? ? ? ? unitDataObject.put("telephone", tel);? ? }try{? ? ? ? JSONArray url = resultItem.getJSONArray("website");if(url !=null&& url.size() >0) {? ? ? ? ? ? unitDataObject.put("detail_url", url.getString(0));? ? ? ? }? ? }catch(Exception e) {? ? ? ? unitDataObject.put("detail_url", resultItem.getString("website"));? ? }? ? JSONArray photos = resultItem.getJSONArray("photos");if(photos !=null&& photos.size() >0) {? ? ? ? StringBuilder images =newStringBuilder();for(intj =0; j < photos.size(); j++) {? ? ? ? ? ? images.append(j ==0?"":";").append(photos.getJSONObject(j).getString("url"));? ? ? ? }? ? ? ? unitDataObject.put("images", images.toString());? ? }? ? String entr_location = resultItem.getString("location");if(StringUtils.isEmpty(entr_location)) {? ? ? ? entr_location = resultItem.getString("entr_location");? ? }if(!StringUtils.isEmpty(entr_location)) {? ? ? ? unitDataObject.put("lng", entr_location.split(",")[0]);? ? ? ? unitDataObject.put("lat", entr_location.split(",")[1]);? ? }returnunitDataObject;}privateStringgetRequestGaodeUrl(RectangleCoordinate coordinate,intpage){return"https://restapi.amap.com/v3/place/polygon?"+"key=xxxxxxxxxxxxxxxxxxxxxxx&polygon="+ coordinate.toString() +"&page="+ page 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* 矩形塊的經緯度標識， 左上角的經緯度 和右下角的經緯度

*/classRectangleCoordinate{/**

? ? * 矩形左上角經度

? ? */privatedoublex0;/**

? ? * 矩形左上角緯度

? ? */privatedoubley0;/**

? ? * 矩形右下角經度

? ? */privatedoublex1;/**

? ? * 矩形右下角緯度

? ? */privatedoubley1;publicRectangleCoordinate(doublex0,doubley0,doublex1,doubley1){this.x0 = x0;this.y0 = y0;this.x1 = x1;this.y1 = y1;? ? }/**? ? *@return獲取矩形中心線的緯度? ? */publicdoublegetAverageY(){return(y0 + y1) /2;? ? }/**? ? *@return獲取矩形中心線的經度? ? */publicdoublegetAverageX(){return(x0 + x1) /2;? ? }publicdoublegetX0(){returnx0;? ? }publicvoidsetX0(doublex0){this.x0 = x0;? ? }publicdoublegetY0(){returny0;? ? }publicvoidsetY0(doubley0){this.y0 = y0;? ? }publicdoublegetX1(){returnx1;? ? }publicvoidsetX1(doublex1){this.x1 = x1;? ? }publicdoublegetY1(){returny1;? ? }publicvoidsetY1(doubley1){this.y1 = y1;? ? }@OverridepublicStringtoString(){returnx0 +","+ y0 +"|"+ x1 +","+ y1;? ? }}`

更新（2018-09-20）：

1栈暇、時間問題麻裁，當前50ms請求一次api接口，跑完小縣城的數(shù)據(jù)（幾萬條）大概需要十分鐘左右吧，把整個市區(qū)主要數(shù)據(jù)跑完斷斷續(xù)續(xù)的用了一天吧煎源，最后跑了近27W數(shù)據(jù)

原文鏈接：https://my.oschina.net/u/1417838/blog/2054570