1逼肯、 runAsync 和 supplyAsync方法
CompletableFuture 提供了四個靜態(tài)方法來創(chuàng)建一個異步操作。
public static CompletableFuture<Void> runAsync(Runnable runnable)
public static CompletableFuture<Void> runAsync(Runnable runnable, Executor executor)
public static <U> CompletableFuture<U> supplyAsync(Supplier<U> supplier)
public static <U> CompletableFuture<U> supplyAsync(Supplier<U> supplier, Executor executor)
沒有指定Executor的方法會使用ForkJoinPool.commonPool() 作為它的線程池執(zhí)行異步代碼。如果指定線程池卢未,則使用指定的線程池運行觅够。以下所有的方法都類同。
- runAsync方法不支持返回值骡苞。
- supplyAsync可以支持返回值垂蜗。
示例
//無返回值
public static void runAsync() throws Exception {
CompletableFuture<Void> future = CompletableFuture.runAsync(() -> {
try {
TimeUnit.SECONDS.sleep(1);
} catch (InterruptedException e) {
}
System.out.println("run end ...");
});
future.get();
}
//有返回值
public static void supplyAsync() throws Exception {
CompletableFuture<Long> future = CompletableFuture.supplyAsync(() -> {
try {
TimeUnit.SECONDS.sleep(1);
} catch (InterruptedException e) {
}
System.out.println("run end ...");
return System.currentTimeMillis();
});
long time = future.get();
System.out.println("time = "+time);
}
2、計算結果完成時的回調方法
當CompletableFuture的計算結果完成解幽,或者拋出異常的時候贴见,可以執(zhí)行特定的Action。主要是下面的方法:
public CompletableFuture<T> whenComplete(BiConsumer<? super T,? super Throwable> action)
public CompletableFuture<T> whenCompleteAsync(BiConsumer<? super T,? super Throwable> action)
public CompletableFuture<T> whenCompleteAsync(BiConsumer<? super T,? super Throwable> action, Executor executor)
public CompletableFuture<T> exceptionally(Function<Throwable,? extends T> fn)
可以看到Action的類型是BiConsumer<? super T,? super Throwable>它可以處理正常的計算結果躲株,或者異常情況片部。
whenComplete 和 whenCompleteAsync 的區(qū)別:
whenComplete:是執(zhí)行當前任務的線程執(zhí)行繼續(xù)執(zhí)行 whenComplete 的任務。
whenCompleteAsync:是執(zhí)行把 whenCompleteAsync 這個任務繼續(xù)提交給線程池來進行執(zhí)行徘溢。
示例
public static void whenComplete() throws Exception {
CompletableFuture<Void> future = CompletableFuture.runAsync(() -> {
try {
TimeUnit.SECONDS.sleep(1);
} catch (InterruptedException e) {
}
if(new Random().nextInt()%2>=0) {
int i = 12/0;
}
System.out.println("run end ...");
});
future.whenComplete(new BiConsumer<Void, Throwable>() {
@Override
public void accept(Void t, Throwable action) {
System.out.println("執(zhí)行完成吞琐!");
}
});
future.exceptionally(new Function<Throwable, Void>() {
@Override
public Void apply(Throwable t) {
System.out.println("執(zhí)行失敗然爆!"+t.getMessage());
return null;
}
});
TimeUnit.SECONDS.sleep(2);
}
3站粟、 thenApply 方法
當一個線程依賴另一個線程時,可以使用 thenApply 方法來把這兩個線程串行化曾雕。
public <U> CompletableFuture<U> thenApply(Function<? super T,? extends U> fn)
public <U> CompletableFuture<U> thenApplyAsync(Function<? super T,? extends U> fn)
public <U> CompletableFuture<U> thenApplyAsync(Function<? super T,? extends U> fn, Executor executor)
Function<? super T,? extends U>
T:上一個任務返回結果的類型
U:當前任務的返回值類型
示例
private static void thenApply() throws Exception {
CompletableFuture<Long> future = CompletableFuture.supplyAsync(new Supplier<Long>() {
@Override
public Long get() {
long result = new Random().nextInt(100);
System.out.println("result1="+result);
return result;
}
}).thenApply(new Function<Long, Long>() {
@Override
public Long apply(Long t) {
long result = t*5;
System.out.println("result2="+result);
return result;
}
});
long result = future.get();
System.out.println(result);
}
第二個任務依賴第一個任務的結果奴烙。
4、 handle 方法
handle 是執(zhí)行任務完成時對結果的處理剖张。
handle 方法和 thenApply 方法處理方式基本一樣切诀。不同的是 handle 是在任務完成后再執(zhí)行,還可以處理異常的任務搔弄。thenApply 只可以執(zhí)行正常的任務幅虑,任務出現(xiàn)異常則不執(zhí)行 thenApply 方法。
public <U> CompletionStage<U> handle(BiFunction<? super T, Throwable, ? extends U> fn);
public <U> CompletionStage<U> handleAsync(BiFunction<? super T, Throwable, ? extends U> fn);
public <U> CompletionStage<U> handleAsync(BiFunction<? super T, Throwable, ? extends U> fn,Executor executor);
示例
public static void handle() throws Exception{
CompletableFuture<Integer> future = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int i= 10/0;
return new Random().nextInt(10);
}
}).handle(new BiFunction<Integer, Throwable, Integer>() {
@Override
public Integer apply(Integer param, Throwable throwable) {
int result = -1;
if(throwable==null){
result = param * 2;
}else{
System.out.println(throwable.getMessage());
}
return result;
}
});
System.out.println(future.get());
}
從示例中可以看出顾犹,在 handle 中可以根據(jù)任務是否有異常來進行做相應的后續(xù)處理操作倒庵。而 thenApply 方法褒墨,如果上個任務出現(xiàn)錯誤,則不會執(zhí)行 thenApply 方法擎宝。
5郁妈、 thenAccept 消費處理結果
接收任務的處理結果,并消費處理绍申,無返回結果噩咪。
public CompletionStage<Void> thenAccept(Consumer<? super T> action);
public CompletionStage<Void> thenAcceptAsync(Consumer<? super T> action);
public CompletionStage<Void> thenAcceptAsync(Consumer<? super T> action,Executor executor);
示例
public static void thenAccept() throws Exception{
CompletableFuture<Void> future = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
return new Random().nextInt(10);
}
}).thenAccept(integer -> {
System.out.println(integer);
});
future.get();
}
從示例代碼中可以看出,該方法只是消費執(zhí)行完成的任務极阅,并可以根據(jù)上面的任務返回的結果進行處理胃碾。并沒有后續(xù)的輸錯操作。
6涂屁、thenRun 方法
跟 thenAccept 方法不一樣的是书在,不關心任務的處理結果。只要上面的任務執(zhí)行完成拆又,就開始執(zhí)行 thenAccept 儒旬。
public CompletionStage<Void> thenRun(Runnable action);
public CompletionStage<Void> thenRunAsync(Runnable action);
public CompletionStage<Void> thenRunAsync(Runnable action,Executor executor);
示例
public static void thenRun() throws Exception{
CompletableFuture<Void> future = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
return new Random().nextInt(10);
}
}).thenRun(() -> {
System.out.println("thenRun ...");
});
future.get();
}
該方法同 thenAccept 方法類似。不同的是上個任務處理完成后帖族,并不會把計算的結果傳給 thenRun 方法栈源。只是處理玩任務后,執(zhí)行 thenAccept 的后續(xù)操作竖般。
7甚垦、thenCombine 合并任務
thenCombine 會把 兩個 CompletionStage 的任務都執(zhí)行完成后,把兩個任務的結果一塊交給 thenCombine 來處理涣雕。
public <U,V> CompletionStage<V> thenCombine(CompletionStage<? extends U> other,BiFunction<? super T,? super U,? extends V> fn);
public <U,V> CompletionStage<V> thenCombineAsync(CompletionStage<? extends U> other,BiFunction<? super T,? super U,? extends V> fn);
public <U,V> CompletionStage<V> thenCombineAsync(CompletionStage<? extends U> other,BiFunction<? super T,? super U,? extends V> fn,Executor executor);
示例
private static void thenCombine() throws Exception {
CompletableFuture<String> future1 = CompletableFuture.supplyAsync(new Supplier<String>() {
@Override
public String get() {
return "hello";
}
});
CompletableFuture<String> future2 = CompletableFuture.supplyAsync(new Supplier<String>() {
@Override
public String get() {
return "hello";
}
});
CompletableFuture<String> result = future1.thenCombine(future2, new BiFunction<String, String, String>() {
@Override
public String apply(String t, String u) {
return t+" "+u;
}
});
System.out.println(result.get());
}
8艰亮、thenAcceptBoth
當兩個CompletionStage都執(zhí)行完成后,把結果一塊交給thenAcceptBoth來進行消耗
public <U> CompletionStage<Void> thenAcceptBoth(CompletionStage<? extends U> other,BiConsumer<? super T, ? super U> action);
public <U> CompletionStage<Void> thenAcceptBothAsync(CompletionStage<? extends U> other,BiConsumer<? super T, ? super U> action);
public <U> CompletionStage<Void> thenAcceptBothAsync(CompletionStage<? extends U> other,BiConsumer<? super T, ? super U> action, Executor executor);
示例
private static void thenAcceptBoth() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
}
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
}
});
f1.thenAcceptBoth(f2, new BiConsumer<Integer, Integer>() {
@Override
public void accept(Integer t, Integer u) {
System.out.println("f1="+t+";f2="+u+";");
}
});
}
9挣郭、applyToEither 方法
兩個CompletionStage迄埃,誰執(zhí)行返回的結果快,我就用那個CompletionStage的結果進行下一步的轉化操作兑障。
public <U> CompletionStage<U> applyToEither(CompletionStage<? extends T> other,Function<? super T, U> fn);
public <U> CompletionStage<U> applyToEitherAsync(CompletionStage<? extends T> other,Function<? super T, U> fn);
public <U> CompletionStage<U> applyToEitherAsync(CompletionStage<? extends T> other,Function<? super T, U> fn,Executor executor);
示例
private static void applyToEither() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
}
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
}
});
CompletableFuture<Integer> result = f1.applyToEither(f2, new Function<Integer, Integer>() {
@Override
public Integer apply(Integer t) {
System.out.println(t);
return t * 2;
}
});
System.out.println(result.get());
}
10侄非、acceptEither 方法
兩個CompletionStage,誰執(zhí)行返回的結果快流译,我就用那個CompletionStage的結果進行下一步的消耗操作逞怨。
public CompletionStage<Void> acceptEither(CompletionStage<? extends T> other,Consumer<? super T> action);
public CompletionStage<Void> acceptEitherAsync(CompletionStage<? extends T> other,Consumer<? super T> action);
public CompletionStage<Void> acceptEitherAsync(CompletionStage<? extends T> other,Consumer<? super T> action,Executor executor);
示例
private static void acceptEither() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
}
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
}
});
f1.acceptEither(f2, new Consumer<Integer>() {
@Override
public void accept(Integer t) {
System.out.println(t);
}
});
}
11、runAfterEither 方法
兩個CompletionStage福澡,任何一個完成了都會執(zhí)行下一步的操作(Runnable)
public CompletionStage<Void> runAfterEither(CompletionStage<?> other,Runnable action);
public CompletionStage<Void> runAfterEitherAsync(CompletionStage<?> other,Runnable action);
public CompletionStage<Void> runAfterEitherAsync(CompletionStage<?> other,Runnable action,Executor executor);
示例
private static void runAfterEither() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
}
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
}
});
f1.runAfterEither(f2, new Runnable() {
@Override
public void run() {
System.out.println("上面有一個已經(jīng)完成了叠赦。");
}
});
}
12、runAfterBoth
兩個CompletionStage革砸,都完成了計算才會執(zhí)行下一步的操作(Runnable)
public CompletionStage<Void> runAfterBoth(CompletionStage<?> other,Runnable action);
public CompletionStage<Void> runAfterBothAsync(CompletionStage<?> other,Runnable action);
public CompletionStage<Void> runAfterBothAsync(CompletionStage<?> other,Runnable action,Executor executor);
示例
private static void runAfterBoth() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
}
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
}
});
f1.runAfterBoth(f2, new Runnable() {
@Override
public void run() {
System.out.println("上面兩個任務都執(zhí)行完成了除秀。");
}
});
}
13窥翩、thenCompose 方法
thenCompose 方法允許你對兩個 CompletionStage 進行流水線操作,第一個操作完成時鳞仙,將其結果作為參數(shù)傳遞給第二個操作。
public <U> CompletableFuture<U> thenCompose(Function<? super T, ? extends CompletionStage<U>> fn);
public <U> CompletableFuture<U> thenComposeAsync(Function<? super T, ? extends CompletionStage<U>> fn) ;
public <U> CompletableFuture<U> thenComposeAsync(Function<? super T, ? extends CompletionStage<U>> fn, Executor executor) ;
示例
private static void thenCompose() throws Exception {
CompletableFuture<Integer> f = CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = new Random().nextInt(3);
System.out.println("t1="+t);
return t;
}
}).thenCompose(new Function<Integer, CompletionStage<Integer>>() {
@Override
public CompletionStage<Integer> apply(Integer param) {
return CompletableFuture.supplyAsync(new Supplier<Integer>() {
@Override
public Integer get() {
int t = param *2;
System.out.println("t2="+t);
return t;
}
});
}
});
System.out.println("thenCompose result : "+f.get());
}