是的話返回整形 否則返回原來(lái)的數(shù)據(jù)
private String isIneger(double d){
String str = d+"";
String[] strings = str.split("\\.");
int i = Integer.parseInt(strings[1]);
return i==0?strings[0]:str;
}
是的話返回整形 否則返回原來(lái)的數(shù)據(jù)
private String isIneger(double d){
String str = d+"";
String[] strings = str.split("\\.");
int i = Integer.parseInt(strings[1]);
return i==0?strings[0]:str;
}