Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).
Find the minimum element.
You may assume no duplicate exists in the array.
public class Solution {
public int findMin(int[] nums) {
int start = 0,end = nums.length-1;
while(nums[start]>nums[end]) //注意限制條件！！！
{
int mid = (start + end)>>1;
System.out.println(nums[mid]);
System.out.println(nums[start]);
if(nums[mid]>=nums[start])
{
start = mid +1;
System.out.println(start);
}
else
{
end = mid;
// System.out.println(end);
}
}
return nums[start];//注意這個(gè)神奇的start或者left!!!
}
}
