Question
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.
Input: "Hello World"
Output: 5
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
- first attempt
class Solution {
public:
int lengthOfLastWord(string s) {
if(s.size()==0)
return 0;
while(s.size()>0&&s.back()==' ')
s.pop_back();
int sum =0;
string::reverse_iterator it;
for(it=s.rbegin();it!=s.rend();it++)
{
if(*it==' ')
return sum;
else
sum++;
}
return sum;
}
};
