◆ 什么是啞表(dual)
?????????啞表的名字為dual,這個(gè)表是虛擬的洒忧,不存在的,主要是用來構(gòu)建或者驗(yàn)證select語 法。這個(gè)表里面永遠(yuǎn)只有一條數(shù)據(jù)碘举,那就是查詢出來的數(shù)據(jù)
◆ 例子
?????????顯示1+1的結(jié)果
?????????????????Select 1+1 from dual;
◆ 單值函數(shù)
?字符函數(shù)
1 lower (args) 返回轉(zhuǎn)換成小寫的字符串
(1)Select lower('GIBK')from dual;
(2)select lower(last_name)froms_emp;
2. upper (args) 轉(zhuǎn)換為大寫的字符串
(1)select upper('ineeo') from dual;
(2)select upper(last_name) froms_emp;
3. initcap (args) 首字母大寫的字符串
(1)select initcap('nico') from dual;
(2)select initcap (userid) froms_emp;
4. length (args) 返回字符串的長度
(1)select length ('bvien')fromdual;
(2)select length (userid)from s_emp;
5. concat(args,agrs1) 連接字符串?????
(1)select concat('hello','-word') from dual;
(2)select concat(first_name,last_name) froms_emp;
(3)嵌套:select concat(concat(first_name,'*'),last_name) froms_emp;
6.substr(args,1,1) 返回截取的字符串
(1)select substr('buanev',1,5) from dual;
(2)select substr(first_name,1,3) froms_emp;
(3)嵌套:
截取最后一個(gè)字母
????select substr('dtfygh',length('dtfygh'),1) from dual;
查詢最后一個(gè)字母為大寫的員工信息,且長度不小于5
????select last_name
????froms_emp
????where length(last_name) >= 5
?????????? and
?????????? substr(upper(last_name),length(last_name) - 1,1)
?????????? =substr(last_name,length(last_name) - 1,1);
7. Nvl(arg1,arg2) 空值函數(shù)
(1)Nvl(arg1,arg2) 如果參數(shù)為空搁廓,返回參數(shù)2
select nvl(commission_pct,-1) froms_emp;
(2)Nvl2(arg1,agr2,agr3)? 如果參數(shù)為空引颈,返回參數(shù)3耕皮,不為空返回參數(shù)2
select nvl2(commission_pct,1,-1)froms_emp;
(3)Nullif(arg1,arg2) 如果參數(shù)1=參數(shù)2 那么就返回null,否則返回參數(shù)1
select nullif(3,3)from dual;
(4)求每個(gè)員工的薪水,基本工資加上提成
select salary+(salary*nvl(commission_pct,1)) froms_emp;
?數(shù)字函數(shù)
1.round(args1,[args2])四舍五入
????select round(45.67) from dual;????? 46
????select round(45.67,1) from dual;?? 45.7
????select round(45.67,2)from dual;?? 45.67
????select round(45.67,-1) from dual;? 50
????select round(45.67,-2)from dual;?? 0
????select round(55.67,-2) from dual;? 100
2. trunc(args1,[args2])截取到某一位
????select trunc(45.67)from dual;???? 45
????select trunc(45.67,1)from dual;?? 45.6
????select trunc(45.67,2)from dual;?? 45.67
????select trunc(45.67,-1)from dual;? 40
????select trunc(45.67,-2)from dual;? 0
????select trunc(55.67,-2)from dual; 0
3. mod(args1,args2) 取余
(1)select mod(10,3) fromdual;? 1
(2)在sql中任何數(shù)對(duì)0取余都是他本身
select mod(130,0)from dual;???? 130
(3)在sql中任何數(shù)對(duì)1取余都是0
select mod('1',2) from dual;??? 0
? 日期函數(shù)
????Sysdate 獲取當(dāng)前時(shí)間
????select sysdate from dual;
????可以日期進(jìn)行加減蝙场,單位是天
????select sysdate -1 from dual;
1.? months_between(args1,args2)倆個(gè)日期之間相差多少個(gè)月【單位是月】
(1)30 天之后和現(xiàn)在相差多少個(gè)月
select months_between(sysdate +30 , sysdate) from dual;???? 1
(2)如果不滿一個(gè)月則返回一個(gè)小數(shù)
select months_between(sysdate +10,sysdate) from dual;?????? 0.32258064516129
2.? add_months(args1,args2) 返回一個(gè)日期數(shù)據(jù):表示一個(gè)時(shí)間點(diǎn),往后推 x 月的日期
(1)'01-2 月-2016'往后推 2 個(gè)月
select add_months('01-2月-2016',2) from dual;
(2)當(dāng)前時(shí)間往前推 4 個(gè)月
select add_months(sysdate,-4) from dual;
(3)select months_between(sysdate,'19-6月-2019') from dual;
(4)select months_between('18-3月-1996','10-9月-2019') from dual;
3.? next_day(args1,args2) 返回日期:表示下一個(gè)星期幾在哪一天
(1)離當(dāng)前時(shí)間最近的下一個(gè)星期 5 是哪一個(gè)天
select next_day(sysdate,'星期五') from dual;
(2)select next_day('18-3月-1996','星期五') from dual;
4. last_day(arg1,args2)返回日期:表示指定月份的最后一天
(1)當(dāng)前日期所在月份的最后一天( 月底)?
select last_day(sysdate) from dual;
(2)select last_day('18-3月-1996') from dual;
5. ROUND 對(duì)日期進(jìn)四舍五入,返回操作后的日期數(shù)據(jù)
(1)把當(dāng)前日期四舍五入到月
select round(sysdate,'MONTH') from dual;
6.? TRUNC 對(duì)日期進(jìn)行截取 和 round 類似,但是只舍棄不進(jìn)位
select trunc(sysdate,'MONTH') from dual;
? 轉(zhuǎn)換函數(shù)
1. to_date(args,agrs)把日期轉(zhuǎn)換為字符
(1)把當(dāng)前日期按照指定格式轉(zhuǎn)換為字符串
select to_char(sysdate,'yyyy-mm-DD') from dual;
(2) 將2016-1-1轉(zhuǎn)換成日期
select to_date('2016-1-1','yyyy-mm-DD') from dual;
1. to_char(agr1,agr2) 把數(shù)字轉(zhuǎn)換為字符
(1)以美元符號(hào)顯示薪水
select to_char(salary,'fm$999,999.00') froms_emp;
【fm】表示【去除】結(jié)果顯示中的【開始的空格】
(2)以本地符號(hào)顯示薪水
select to_char(salary,'fmL999,999.00')??? from s_emp;
【fmL】表示本地符號(hào)
4. to_number(agrs) 把字符轉(zhuǎn)換為日期
select to_number('0100') from dual;??? 100
注:都顯示的是十進(jìn)制
select to_number('01010101') from dual;?????? 1010101