1.輸入一個字符串,打印所有奇數(shù)位上的字符(下標是1,3属提,5寂汇,7…位上的字符)
例如: 輸入'abcd1234 ' 輸出'bd24'
str1 = input('請輸入字符串:')
print(str1[1::2])
2.輸入用戶名病往,判斷用戶名是否合法(用戶名長度6~10位)
value = input('請輸入用戶名:')
count = len(value)
if count < 6 or count > 10:
print('不合法')
else:
print('合法')
3.輸入用戶名,判斷用戶名是否合法(用戶名中只能由數(shù)字和字母組成)
# 方法一:
value = input('請輸入用戶名:')
count1 = 0
count2 = 0
for char in value:
count1 += 1
if '0' <= char <= '9' or 'a' <= char <= 'z' or 'A' <= char <= 'Z':
count2 += 1
if count1 == count2:
print('合法')
else:
print('不合法')
# 方法二:
value = input('請輸入用戶名:')
for char in value:
if not('0' <= char <= '9' or 'a' <= char <= 'z' or 'A' <= char <= 'Z'):
print('不合法')
break
else:
print('合法')
4.輸入用戶名骄瓣,判斷用戶名是否合法(用戶名必須包含且只能包含數(shù)字和字母停巷,并且第一個字符必須是大寫字母)
value = input('請輸入用戶名:')
count = 0
count1 = 0
count2 = 0
for char in value:
if not'A' <= value[0] <= 'Z':
break
count += 1
if '0' <= char <= '9':
count1 += 1
if 'a' <= char <= 'z' or 'A' <= char <= 'Z':
count2 += 1
if count == count1 + count2 and count1 > 0 and count2 >0:
print('合法')
else:
print('不合法')
5.輸入一個字符串,將字符串中所有的數(shù)字字符取出來產(chǎn)生一個新的字符串
value = input('請輸入一個字符串:')
for char in value:
if '0' <= char <= '9':
print(char, end=' ')
6.輸入一個字符串累贤,將字符串中所有的小寫字母變成對應的大寫字母輸出
value = input('請輸入一個字符串:')
x1 = ''
for char in value:
if 'a' <= char <= 'z':
x1 += char
print(x1.upper())
7.輸入一個小于1000的數(shù)字叠穆,產(chǎn)生對應的學號。例如: 輸入'23'臼膏,輸出'py1901023' 輸入'9', 輸出'py1901009' 輸入'123'硼被,輸出'py1901123'
value = input('請輸入數(shù)字:')
print('py1901', str(value).zfill(3), sep='')
8.輸入一個字符串,統(tǒng)計字符串中非數(shù)字字母的字符的個數(shù)渗磅。例如: 輸入'anc2+93-sj胡說' 輸出:4 輸入'===' 輸出:3
value = input('請輸入數(shù)字:')
count = 0
for char in value:
if not('0' <= char <= '9' or 'a' <= char <= 'z' or 'A' <= char <= 'Z'):
count += 1
print(count)
9.輸入字符串嚷硫,將字符串的開頭和結尾變成'+',產(chǎn)生一個新的字符串始鱼。例如: 輸入字符串'abc123', 輸出'+bc12+'
str1 = input('請輸入一個字符串:')
n = len(str1)-1
str1 = str1[1:n:]
print('+', str1, '+', sep='')
10.輸入字符串仔掸,獲取字符串的中間字符。例如: 輸入'abc1234' 輸出:'1' 輸入'abc123' 輸出'c1'
str1 = input('請輸入一個字符串:')
n1 = len(str1)
n2 = int(n1/2)
if n1 % 2 == 0:
print(str1[n2-1:n2+1:])
else:
print(str1[n2:n2+1:])