GRE? Quantitative Reasoning Introduction
機(jī)考? section-level 自適應(yīng)性考試党瓮，可翻頁可修改
2 sections:20 questions/35min/ per section
題型:
1.數(shù)量比較題
2.單項(xiàng)選擇題
3.不定項(xiàng)選擇題
4.數(shù)字填空題
一.算術(shù)
整數(shù)的屬性和類型（可分性外里、因式分解、質(zhì)數(shù)、余數(shù)窃祝、奇偶數(shù)）
算術(shù)運(yùn)算桩了、指數(shù)、根式
概念:百分比夕土、比率馆衔、比例、絕對(duì)值怨绣、數(shù)軸角溃、十進(jìn)制、數(shù)列
余數(shù)因子類問題
基本概念:
Positive Integer, quotient, remainder Factor(divisor), prime factor, multipleCommon factor, common multiple
y/x= y is divided by x
y is divisible by x
x is a factor of y
x is a divisor of y
y is a multiple of x
100以內(nèi)的質(zhì)數(shù)prime number：2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97 （共25個(gè)）
余數(shù)定理
1.余同取余
一個(gè)數(shù)除以4余1篮撑，除以5余1减细，除以6余1，則可表示為60N＋1
2.和同取和
一個(gè)數(shù)除以4余3赢笨，除以5余2未蝌，除以6余1，則可表示為60N＋7
3.差同取差
一個(gè)數(shù)除以4余1茧妒，除以5余2萧吠，除以6余3，則可表示為60N－3
小結(jié):
①質(zhì)因數(shù)
②A=B·k
③a^b與a桐筏，distinct prime factor
④a·b=LCM×GCD
⑤N=2×3×5×7
? ? ? =2^2×3^5×5^2? number of prime factors
⑥余／除=decimal? part
⑦x/a=Q···R? x=aQ+R
⑧X=7a＋3=2b＋5
⑨(M·N)mod a=(M mod a)·(N mod a)mod a
①what fraction of A is B:? B/A
②A→B
the precentage increase from A to B
(B－A)/A·100％=100(B－A)/A％
③the ratio of A to B:? A/B
④a→b
increase by what factor from a to b: b/a
①a＋b－x＋e＝Total
②a＋b＋c－2x－y＋e＝Total
