1.因?yàn)樵撨B續(xù)序列是公差為1的序列默蚌,所以它們的和為cur = (low +high)*(high-low+1)/2
2.設(shè)置兩個(gè)指針宇整,當(dāng)當(dāng)前的和小于sum時(shí)候high高指針加一蝗羊,當(dāng)?shù)扔诘臅r(shí)候?qū)⑦B續(xù)序列存起來趴拧,并且將low指針加1婆誓,當(dāng)和大于sum的指針的時(shí)候吭露,low++;
1.因?yàn)樵撨B續(xù)序列是公差為1的序列默蚌,所以它們的和為cur = (low +high)*(high-low+1)/2
2.設(shè)置兩個(gè)指針宇整,當(dāng)當(dāng)前的和小于sum時(shí)候high高指針加一蝗羊,當(dāng)?shù)扔诘臅r(shí)候?qū)⑦B續(xù)序列存起來趴拧,并且將low指針加1婆誓,當(dāng)和大于sum的指針的時(shí)候吭露,low++;