又是同一類型的題目但是卻又沒(méi)有輕易地ac，這個(gè)原因我至今沒(méi)找到，應(yīng)該是輸出部分的代碼有問(wèn)題，有一個(gè)測(cè)試點(diǎn)一直顯示答案錯(cuò)誤嚎货，換成柳神的輸出代碼便ac了。
#include <iostream>
using namespace std;
int main() {
int n, grade;
string name, id, hname, lname, hid, lid, gender;
int max = -1, min = 101;
scanf("%d", &n);
for(int i = 0; i < n; i++){
cin >> name >> gender >> id;
scanf("%d", &grade);
if(gender == "F"){
if(grade > max){
max = grade;
hname = name;
hid = id;
}
}
else if(gender == "M"){
if(grade < min){
min = grade;
lname = name;
lid = id;
}
}
}
if(max != -1)
cout << hname << " " << hid << endl;
else
printf("Absent\n");
if(min != 101)
cout << lname << " " << lid << endl;
else
printf("Absent\n");
if(max != -1 && min != 101)
printf("%d", max - min);
else
printf("NA");
return 0;
}
之前我的輸出部分的代碼是這樣的：
if(max == -1 )
cout << "Absent" << endl << lname << " " << lid << endl << "NA";
else if(min == 101)
cout << "Absent" << endl << hname << " " << hid << endl << "NA";
else if(max != -1 && min != 101){
cout << hname<< " " << hid << endl;
cout << lname << " " << lid << endl << max - min;
}
不過(guò)這段代碼看上去就啰嗦得很一點(diǎn)也不簡(jiǎn)潔蔫浆。
