來(lái)源:力扣(LeetCode)
鏈接:https://leetcode-cn.com/problems/binary-tree-level-order-traversal/
題目描述
給你一個(gè)二叉樹(shù)铃将,請(qǐng)你返回其按 層序遍歷 得到的節(jié)點(diǎn)值迫悠。 (即逐層地,從左到右訪問(wèn)所有節(jié)點(diǎn))廊营。
【 二叉樹(shù)的后序遍歷節(jié)點(diǎn)訪問(wèn)順序:左節(jié)點(diǎn)、右節(jié)點(diǎn)霜运、根節(jié)點(diǎn)】
【二叉樹(shù)的中序遍歷節(jié)點(diǎn)訪問(wèn)順序:左節(jié)點(diǎn)勾邦、根節(jié)點(diǎn)、右節(jié)點(diǎn)】
【二叉樹(shù)的前序遍歷節(jié)點(diǎn)訪問(wèn)順序:根節(jié)點(diǎn)午衰、左節(jié)點(diǎn)立宜、右節(jié)點(diǎn)】
題目分析
提供兩種方法實(shí)現(xiàn):
- BFS(Breath First Search)廣度優(yōu)先搜索【推薦使用】
- DFS(Deep First Search)深度優(yōu)先搜索
代碼實(shí)現(xiàn)
public class LevelOrder {
public static void main(String[] args) {
LevelOrder preOrder = new LevelOrder();
/**
* 1
* 10 2
* 3 9
*/
TreeNode root = new TreeNode(1, new TreeNode(10), new TreeNode(2, new TreeNode(3), new TreeNode(9)));
// TreeNode root = null;
preOrder.levelOrder2(root);
preOrder.levelOrder(root);
}
/**
* 隊(duì)列
* BFS(Breath First Search)廣度優(yōu)先搜索
* queue.offer(root); 末尾追加元素
* queue.peek(); 隊(duì)首出隊(duì)
* queue.poll(); 獲取隊(duì)首元素
*
* @param root
* @return
*/
public List<List<Integer>> levelOrder(TreeNode root) {
List<List<Integer>> result = new ArrayList<List<Integer>>();
if (root == null) {
return result;
}
Queue<TreeNode> queue = new LinkedList();
queue.offer(root);
while (!queue.isEmpty()) {
List<Integer> subList = new ArrayList<Integer>();
int currSize = queue.size();
for (int i = 0; i < currSize; i++) {
TreeNode currNode = queue.poll();
subList.add(currNode.val);
if (currNode.left != null) {
queue.offer(currNode.left);
}
if (currNode.right != null) {
queue.offer(currNode.right);
}
}
result.add(subList);
}
System.out.println(result);
return result;
}
/**
* DFS(Deep First Search)深度優(yōu)先搜索
*
* @param root
* @return
*/
public List<List<Integer>> levelOrder2(TreeNode root) {
List<List<Integer>> result = new ArrayList<List<Integer>>();
order(root, result, 0);
System.out.println(result);
return result;
}
private void order(TreeNode root, List<List<Integer>> list, int level) {
if (root == null) {
return;
}
if (level >= list.size()) {
list.add(new ArrayList<Integer>());
}
list.get(level).add(root.val);
order(root.left, list, level + 1);
order(root.right, list, level + 1);
}
}
BFS復(fù)雜度
- 時(shí)間復(fù)雜度:O(n)
- 空間復(fù)雜度:O(n)
好了,今天就到這里臊岸,感謝各位看官到這里橙数,不如點(diǎn)個(gè)關(guān)注吧!