題外話：最近一直很閑野瘦，項(xiàng)目上基本沒有啥大的需求描沟。對于程序員來說，如果沒有需求其實(shí)是一件很難受的事情鞭光，之前好多次在項(xiàng)目中沒事找事吏廉，該優(yōu)化的優(yōu)化，該整理的整理惰许∠玻可能好多程序員都遇到過與我類似的情況。但是程序員真的需要通過刷項(xiàng)目去提高自己嗎啡省？程序員的功力體現(xiàn)在處理項(xiàng)目的細(xì)節(jié)上娜睛，有可能為了改進(jìn)一點(diǎn)點(diǎn)的體驗(yàn)就要付出很大的代價(jià)，就要接觸更多的知識點(diǎn)卦睹。做的項(xiàng)目多，但是不精那么只能代表自己在比較淺顯的領(lǐng)域比較熟練而已方库。以上觀點(diǎn)是我在最近思考得來的结序，并不一定正確，甚至明天一早我就會推翻這種想法纵潦，請大家謹(jǐn)慎參考??徐鹤。

一、什么是隔離導(dǎo)航控制器邀层？

這個(gè)名詞純粹是我自己瞎編的返敬，我不知道有沒有這種說法，至少我沒有看到寥院。我所說的隔離導(dǎo)航控制器是指：在導(dǎo)航欄樣式不同的頁面采用不同的導(dǎo)航控制器【⒃現(xiàn)在同一個(gè)導(dǎo)航欄發(fā)生變化主要體現(xiàn)在：隱藏導(dǎo)航欄頁面跳轉(zhuǎn)到非隱藏導(dǎo)航欄的頁面、A顏色導(dǎo)航欄的頁面跳轉(zhuǎn)到B顏色導(dǎo)航欄的頁面秸谢、可跟隨滑動做動畫的頁面跳轉(zhuǎn)到固定導(dǎo)航欄的頁面凛澎。隔離導(dǎo)航控制器就是：當(dāng)頁面跳轉(zhuǎn)到導(dǎo)航欄不同的頁面時(shí)不再使用同一個(gè)導(dǎo)航控制器，而是彈出一個(gè)新的導(dǎo)航控制器估蹄，這個(gè)導(dǎo)航控制器的導(dǎo)航欄固定不變塑煎，如果發(fā)生變化那么再彈出一個(gè)新的導(dǎo)航控制器。

二臭蚁、為什么要隔離導(dǎo)航控制器最铁？

很簡單讯赏，因?yàn)槲乙呀?jīng)受夠了頁面的來回跳轉(zhuǎn)導(dǎo)致狀態(tài)欄儲存、變化冷尉、恢復(fù)這樣的過程待逞。尤其在側(cè)滑或者全屏滑動返回時(shí)，導(dǎo)航欄的變化會有不好的體驗(yàn)网严。所以在很久以前我就在醞釀识樱，如果present出來一個(gè)導(dǎo)航控制器就好了（隔離導(dǎo)航控制器并不是一個(gè)很好地解決辦法，但是可以試一試震束，畢竟我很閑）怜庸。因此我在項(xiàng)目中試了一下，結(jié)果遇到了一些問題垢村，自己挖的坑割疾，跪著也要填滿了。

三嘉栓、實(shí)現(xiàn)右進(jìn)右出的present

ViewController 的present樣式一共有4種：

typedef NS_ENUM(NSInteger, UIModalTransitionStyle) {
    UIModalTransitionStyleCoverVertical = 0,//默認(rèn)
    UIModalTransitionStyleFlipHorizontal __TVOS_PROHIBITED,//翻轉(zhuǎn)
    UIModalTransitionStyleCrossDissolve,//透明度漸變
    UIModalTransitionStylePartialCurl NS_ENUM_AVAILABLE_IOS(3_2) __TVOS_PROHIBITED,//翻書
};

[vc setModalTransitionStyle:UIModalTransitionStyleFlipHorizontal];    //present 前加上這句就行
[self presentViewController:vc animated:YES completion:nil];

沒有我們需要的效果宏榕，因此我們需要利用iOS 7 以后的轉(zhuǎn)場動畫來實(shí)現(xiàn)。說到轉(zhuǎn)場動畫不怕大家笑話侵佃，我已經(jīng)看了好多遍了麻昼，但是依然記不住那些名字。每次要用都要去大神的博客里再學(xué)習(xí)一邊馋辈。我的代碼也是使用大神的代碼抚芦，因?yàn)橛X得沒有必要再寫一遍。只不過我做了略微的修改迈螟。

// NormalDismissAnimation
// 4. Do animate now
    NSTimeInterval duration = [self transitionDuration:transitionContext];
    toVC.view.transform = CGAffineTransformMakeTranslation(-100, 0);//主要是為了上下兩個(gè)控制器有聯(lián)動的效果
    [UIView animateWithDuration:duration delay:0 options:UIViewAnimationOptionCurveEaseInOut animations:^{
        fromVC.view.frame = finalFrame;
        toVC.view.transform = CGAffineTransformIdentity;
 
    } completion:^(BOOL finished) {
        [transitionContext completeTransition:![transitionContext transitionWasCancelled]];
    }];
 
 
//BouncePresentAnimation
  // 4. Do animate now
    NSTimeInterval duration = [self transitionDuration:transitionContext];
    [UIView animateWithDuration:duration delay:0 options:UIViewAnimationOptionCurveEaseInOut animations:^{
        toVC.view.frame = finalFrame;
        fromVC.view.transform = CGAffineTransformMakeTranslation(-100, 0);//主要是為了有上下兩個(gè)控制器聯(lián)動的效果
    } completion:^(BOOL finished) {
        fromVC.view.transform = CGAffineTransformIdentity;
        [transitionContext completeTransition:YES];
    }];
 
 
//SwipeUpInteractiveTransition
- (void)handleGesture:(UIPanGestureRecognizer *)gestureRecognizer {
    CGPoint translation = [gestureRecognizer translationInView:gestureRecognizer.view.superview];
       switch (gestureRecognizer.state) {
        case UIGestureRecognizerStateBegan:
            // 1. Mark the interacting flag. Used when supplying it in delegate.
            self.interacting = YES;
            [self.presentingVC dismissViewControllerAnimated:YES completion:nil];
            break;
        case UIGestureRecognizerStateChanged: {
            // 2. Calculate the percentage of guesture
            CGSize screenSize = [UIScreen mainScreen].bounds.size;
            CGFloat fraction = translation.x / screenSize.width;
            //Limit it between 0 and 1
            fraction = fminf(fmaxf(fraction, 0.0), 1.0);
            self.shouldComplete = (fraction > 0.4);
 
            [self updateInteractiveTransition:fraction];
            break;
        }
        case UIGestureRecognizerStateEnded:
        case UIGestureRecognizerStateCancelled: {
            // 3. Gesture over. Check if the transition should happen or not
            self.interacting = NO;
            if (!self.shouldComplete || gestureRecognizer.state == UIGestureRecognizerStateCancelled) {
                [self cancelInteractiveTransition];
            } else {
                [self finishInteractiveTransition];
            }
            break;
        }
        default:
            break;
    }
}

以上部分很簡單而且并不是我們所關(guān)心的部分（雖然名字有點(diǎn)難記憶叉抡，但是不難理解）。完成以上代碼答毫，就可以實(shí)現(xiàn)滑動返回+右進(jìn)右出的present樣式了褥民。

//還有一點(diǎn)需要注意的是，需要禁止全屏手勢在導(dǎo)航控制器棧里有多個(gè)元素時(shí)響應(yīng)
- (BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer{
    if ([self.presentingVC isKindOfClass:[BaseNavigationController class]]) {
        BaseNavigationController *nav = (BaseNavigationController*)self.presentingVC;
        if (nav.viewControllers.count >=2) {
            return NO;
        }
    }
    return YES;
}

四洗搂、遇到的問題

我們（或者說大多數(shù)APP）都有這樣的需求消返，當(dāng)收到推送時(shí)需要從底部彈出一個(gè)ViewController。 但是因?yàn)槲覀兪莗resent 出來了一些頁面蚕脏，當(dāng)收到推送的時(shí)候我們并不能一下子知道從哪個(gè)ViewController 上present 出來一個(gè)需要用戶響應(yīng)的控制器侦副。比方說 HomeViewController ---(右進(jìn)右出present)---->ReportMessageViewController后，從代碼的角度我們不能一下子拿到展現(xiàn)在用戶面前的控制器（因?yàn)槟悴恢朗欠褚呀?jīng)present了驼鞭，也不知道誰調(diào)用的present）秦驯。因此我遇到了第一個(gè)問題（很多的項(xiàng)目可以通過tab、nav 來確定挣棕，而且present 出控制器的場景比較固定）：

1译隘、到底誰是當(dāng)前正在響應(yīng)的控制器亲桥？

要想解決這個(gè)問題我們首先要知道響應(yīng)者鏈條。即當(dāng)我們點(diǎn)擊了屏幕上的一個(gè)按鈕固耘，事件是怎么傳遞的题篷。UIView 和 UIViewController 都是繼承自UIResponder的，他們都可以成為響應(yīng)者厅目。因此我們只要遍歷屏幕上最上方的那些View(葉子節(jié)點(diǎn))番枚，縱向循環(huán)找到他們的nextResponder，直至找到為UIViewController類的響應(yīng)者损敷。

// 獲取某個(gè)view 的葉子 View(一般為Window)
/*
 
*/
+(NSMutableArray *)getTopSubViewsWithParentView:(UIView *)rootView{
    NSMutableArray *stack = [NSMutableArray array];
    NSMutableArray *leafNodes = [NSMutableArray array];//存放葉子節(jié)點(diǎn)
    if (rootView.subviews.count == 0) {
        return nil;
    }
    [stack addObjectsFromArray:rootView.subviews];//把根視圖的所有第一層子視圖入棧
    while (stack.count != 0) {
        UIView *subView = [stack lastObject];//取出頂部元素并判斷是否為葉子節(jié)點(diǎn)
        [stack removeLastObject];
        if (subView.subviews.count != 0) {//不是葉子節(jié)點(diǎn)的話將其子視圖繼續(xù)入棧
            [stack addObjectsFromArray:subView.subviews];
        }else{
            [leafNodes addObject:subView];//如果是葉子節(jié)點(diǎn)則將其入棧（葉子節(jié)點(diǎn)的棧）
        }
    }
    return leafNodes;
}
 
//獲取某個(gè)視圖在哪個(gè)控制器上
+(UIViewController*)getViewControllerWithView:(UIView*)view{
     
    UIResponder *res = view;
    while (res) {
        if (res.nextResponder) {
            res = res.nextResponder;
        }
        if ([res isKindOfClass:[UIViewController class]]) {
             
            UIViewController *vc = (UIViewController*)res;
            return vc;
        }
    }
    return nil;
}
 
//這段代碼的意思是葫笼，如果我能判斷的更精確就精確些。比如某個(gè)導(dǎo)航控制器拗馒，你說他在響應(yīng)也行路星，他的top元素在響應(yīng)也行，顯然我想精確到top元素
+(UIViewController*)getCurrentVC{
    UIWindow *keyWindow = [UIApplication sharedApplication].keyWindow;
     
    NSMutableArray *array = [self getTopSubViewsWithParentView:keyWindow];
    UINavigationController *nav = nil;
    UITabBarController *tab = nil;
    for (UIView *subView in array) {
         
        UIViewController *vc = [self getViewControllerWithView:subView];
        if (!([vc isKindOfClass:[UINavigationController class]] || [vc isKindOfClass:[UITabBarController class]])) {
            return vc;
        }
        if ([vc isKindOfClass:[UINavigationController class]]) {
            nav = (UINavigationController*)vc;
        }
        if ([vc isKindOfClass:[UITabBarController class]]) {
            tab = (UITabBarController *)vc;
        }
    }
    if (nav) {
        return nav;
    }
    if (tab) {
        return tab;
    }
    return nil;
}

有了這些代碼诱桂，問題一就解決了洋丐。

2、全屏滑動遇到了可以左右滑動的ScrollView怎么辦？

首先說明一下，這個(gè)問題我解決的并不完美项乒，因?yàn)槿コ薭ounces 效果。因?yàn)榛瑒覵crollView時(shí)九榔，ScrollView 的pan 手勢會優(yōu)先響應(yīng)，并阻止其他手勢響應(yīng)涡相。首先我們先看一下手勢代理，看看都有哪些方法：

 1 @protocol UIGestureRecognizerDelegate <NSObject>
 2 @optional
 3 // called when a gesture recognizer attempts to transition out of UIGestureRecognizerStatePossible. returning NO causes it to transition to UIGestureRecognizerStateFailed
 4 - (BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer;
 5 
 6 // called when the recognition of one of gestureRecognizer or otherGestureRecognizer would be blocked by the other
 7 // return YES to allow both to recognize simultaneously. the default implementation returns NO (by default no two gestures can be recognized simultaneously)
 8 //
 9 // note: returning YES is guaranteed to allow simultaneous recognition. returning NO is not guaranteed to prevent simultaneous recognition, as the other gesture's delegate may return YES
10 - (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer;//手勢1剩蟀、手勢2 是否可以共存催蝗，即兩者都響應(yīng)，收到事件繼續(xù)傳遞下去
11 
12 // called once per attempt to recognize, so failure requirements can be determined lazily and may be set up between recognizers across view hierarchies
13 // return YES to set up a dynamic failure requirement between gestureRecognizer and otherGestureRecognizer
14 //
15 // note: returning YES is guaranteed to set up the failure requirement. returning NO does not guarantee that there will not be a failure requirement as the other gesture's counterpart delegate or subclass methods may return YES
16 - (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRequireFailureOfGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer NS_AVAILABLE_IOS(7_0);//在other 響應(yīng)的情況下育特，自己是否不響應(yīng)
17 - (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldBeRequiredToFailByGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer NS_AVAILABLE_IOS(7_0);
18 
19 // called before touchesBegan:withEvent: is called on the gesture recognizer for a new touch. return NO to prevent the gesture recognizer from seeing this touch
20 - (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch;
21 
22 // called before pressesBegan:withEvent: is called on the gesture recognizer for a new press. return NO to prevent the gesture recognizer from seeing this press
23 - (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceivePress:(UIPress *)press;

通過打印scrollView 的pan手勢我們會發(fā)現(xiàn) pan手勢的代理是scrollView 丙号，我嘗試過改變pan 的delegate 但是發(fā)現(xiàn)會崩潰，apple 是不允許改變這個(gè)delegate 的缰冤。所以我想到了寫一個(gè)UIScrollView的子類犬缨。

//
//  PanScrollView.m
//  Property
//
//  Created by 高雅馨on 16/7/25.
//  Copyright ? 2016年  高雅??. All rights reserved.
//
 
#import "PanScrollView.h"
 
@implementation PanScrollView
 
-(instancetype)init{
    if (self = [super init]) {
        self.bounces = NO;
    }
    return self;
}
 
/*
 是否將相應(yīng)傳遞給other
  
  
 當(dāng)偏移量X值為0的時(shí)候全屏手勢和pan 手勢同時(shí)響應(yīng)。全屏手勢向右滑動時(shí) 棉浸，由于bounces效果已經(jīng)被去掉了怀薛，所以偏移量不變，ViewController 只有dismiss 效果迷郑。當(dāng)向左滑動時(shí)全屏手勢沒有任何效果枝恋，只要scroll效果创倔。
 */
 
- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer{
     
    if (gestureRecognizer == self.panGestureRecognizer  && otherGestureRecognizer == self.otherGes){
        if (self.contentOffset.x==0) {
            return YES;
        }
    }
    return NO;
}
 
@end

至此，大部分可見的問題解決了焚碌，可能并不完美畦攘，也不適合，但是嘗試也是一種美好的回憶十电，希望能對大家有幫助知押。