問(wèn)：定義一個(gè)過(guò)程，它以三個(gè)數(shù)為參數(shù)垃你，返回其中較大的兩個(gè)數(shù)之和
解：
(define min(a b)
(if (< a b) a b)
)
(define minnum(a b c)
(min(min a b) c)
)
(define sumbig( a b c)
(
COND(= a minnum(a b c ))
(+ b c)
COND(= b minnum(a b c ))
(+ a c)
COND(= c minnum(a b c ))
(+ a b)
)
)
