Question
Write a program that outputs the string representation of numbers from 1 to n.
But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.
Answer
程序中主要使用了
- for i in start .. end循環(huán)結(jié)構(gòu)寨腔，也可以用 times,while實現(xiàn)
- if then else 選擇結(jié)構(gòu)
- % 求余運算
- and 與邏輯運算
- 數(shù)組<<運算符 ：數(shù)組元素追加，ruby的數(shù)組比較靈活啼止，聲明時可以不申明大小垄潮。
- 方法定義：def function_name(args,...) ... end
# @param {Integer} n
# @return {String[]}
def fizz_buzz(n)
result = Array.new()
for i in 1 .. n
if i % 3 == 0 and i % 5==0 then
result << "FizzBuzz"
else
if i % 3 == 0 then
result << "Fizz"
else
if i % 5 == 0 then
result << "Buzz"
else
result << "#{i}"
end
end
end
end
return result
end
